Answer:
i think it will be chose 3 times
Step-by-step explanation:
im not sure thats my pridiction
<span>1. To
solve this problem you must apply the formula for calcúlate the area of a
trapezoid, which is shown below:
A=(B+b)h/2
A is the area of the trapezoid (A=24).
B is the larger base </span>of the trapezoid <span>(B=5).
b is the smaller base </span>of the trapezoid<span> (b=5).
h is the height </span><span>of the trapezoid.
2. You must clear "h" from the formula:
</span><span>
A=(B+b)h/2
</span> 2A=<span>(B+b)h
</span> h=2A/<span>(B+b)
</span><span>
3. When you susbtitute the values into </span> h=2A/(B+b), you obtain:
h=2A/<span>(B+b)
</span><span> h=2(24)/(5+3)
h=48/8
h=6
</span>
The maximum height of the rocket path is : 597 meters
<h3>
Meaning of Maximum height</h3>
Height can be defined as the vertical distance from a point of reference. it can also be said to be the difference between two points being measured vertically
Maximum height is the max or highest vertical distance between two points. its the point a thing gets to vertically that serves as the limit to which it can go.
In conclusion, The maximum height of the rocket path is 597 meters\
Learn more about maximum height: brainly.com/question/12446886
#SPJ1
Answer:
When they are equal, y=y, so we can say:
x^2+5x-2=x+1 subtract x from both side
x^2+4x-2=1 add 2 to both sides
x^2+4x=3, now add half the linear coefficient squared, (4/2)^2=4
x^2+4x+4=3+4 now the left side is a perfect square
(x+2)^2=7 now take the square root of both sides
x+2=±√7 subtract 2 from both sides
x=-2±√7
x=-2+√7 and -2-√7
y=x+1 the two points where these equations are equal are:
(-2-√7, -1-√7) and (-2+√7, -1+√7)
or approximately:
(-4.65, -3.65) and (0.65, 1.65)
Step-by-step explanation:
We compute for the surface area of the triangular prism by the adding the areas of the bases and the sides. There are two triangles and the areas will be,
A = 2 (1/2)(9 cm)(12 cm) = 108 cm²
There are three sides which are in rectangular shape.
A1 = (10)(12) = 120 cm²
A2 = (10)(9) = 90 cm²
A3 = (10)(15) = 150 cm²
The sum of these areas is 468 cm².
