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Lilit [14]
2 years ago
12

There were 400 sweets in a pack. The principal of a school bought 25 such packs of sweets for 2000 children o Children's Day. If

each child was given 7 sweets, how many more packs of sweets were needed?
Mathematics
2 answers:
AlexFokin [52]2 years ago
8 0

Answer:

10 more packs

Step-by-step explanation:

400 sweets bought 25 such packs = 400*25=10000

2000 each one gets 7 = 2000*7=14000

14000-10000=4000

4000/400 is 10.

So 10 more packs.

Hit the crown :D

sattari [20]2 years ago
3 0

Answer:

Step-by-step explanation:

400 sweets in a pack * 25 packs = 10,000 sweets

2000 kids * 7 sweets = 14,000

We need 4,000 more sweets. That would be 10 packs more  since there are 400 sweets in a pack.

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Answer:

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Step-by-step explanation:

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3 years ago
The explicit rule for a sequence is an=5(−2)^n−1
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Answer:

3) a_n=-2a_{n-1}, a_1=5

Step-by-step explanation:

Given that the explicit rule for a sequence is a_n=5(-2)^{n-1}.

Now we need to find about what is the recursive rule for the sequence and match with the given choices to find the correct choice.

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7 0
2 years ago
Initially, there were only 197 weeds at a park. The weeds grew at a rate of 25% each week. The following function represents the
olganol [36]

Answer:

 none of the above

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Step-by-step explanation:

If we let x represent days, then x/7 represents weeks and we can rewrite f(x) as ...

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The daily multiplier of 1.03 represents a daily growth rate of

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_____

These answers are not found among the offered choices:

f(x) = 197·1.03^x

3% daily growth

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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