$3.00 I think. Hope this helps
Answer:
P(B|A)=0.25 , P(A|B) =0.5
Step-by-step explanation:
The question provides the following data:
P(A)= 0.8
P(B)= 0.4
P(A∩B) = 0.2
Since the question does not mention which of the conditional probabilities need to be found out, I will show the working to calculate both of them.
To calculate the probability that event B will occur given that A has already occurred (P(B|A) is read as the probability of event B given A) can be calculated as:
P(B|A) = P(A∩B)/P(A)
= (0.2) / (0.8)
P(B|A)=0.25
To calculate the probability that event A will occur given that B has already occurred (P(A|B) is read as the probability of event A given B) can be calculated as:
P(A|B) = P(A∩B)/P(B)
= (0.2)/(0.4)
P(A|B) =0.5
It would be y=8x+2/3
Explanation:
Y=|3/4x| is an absolute value
Y=x^3+8 is quadratic
Y=8+5/6x^2 is also quadratic (you can tell it’s quadratic because it has an exponent)
Answer:
29
Step-by-step explanation:
because 32-+3=29
