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Lilit [14]
3 years ago
12

There were 400 sweets in a pack. The principal of a school bought 25 such packs of sweets for 2000 children o Children's Day. If

each child was given 7 sweets, how many more packs of sweets were needed?
Mathematics
2 answers:
AlexFokin [52]3 years ago
8 0

Answer:

10 more packs

Step-by-step explanation:

400 sweets bought 25 such packs = 400*25=10000

2000 each one gets 7 = 2000*7=14000

14000-10000=4000

4000/400 is 10.

So 10 more packs.

Hit the crown :D

sattari [20]3 years ago
3 0

Answer:

Step-by-step explanation:

400 sweets in a pack * 25 packs = 10,000 sweets

2000 kids * 7 sweets = 14,000

We need 4,000 more sweets. That would be 10 packs more  since there are 400 sweets in a pack.

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Which ordered pairs could be points on a line parallel to the line that contains (3, 4) and (–2, 2)? Check all that apply.
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Use the slope-intercept form of the equation of a straight line:

y = mx + b becomes 4 = (4/5)(3) + b.  Multiplying all three terms by 5, we eliminate the fraction:  20 = 12 + b.  Thus, b = 8, and the equation of the line through (–2, 2) and (3, 4) is y = (4/5)x + 8.

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3 years ago
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A music store sold a total of 27 used trumpets and clarinets in one month. Trumpets cost $149 and clarinets cost $99. If total s
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Answer:

The number of clarinets musical store sold was 16. and number of trumpets musical store sold was 11.

Step-by-step explanation:

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x+y=27 \Rightarrow x+16=27 \Rightarrow x=27-16=11

Thus, number of trumpets musical store sold was 11.


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