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3 years ago

7

-6+(-1)= ..................

2 answers:

Mice21 [21]3 years ago

8 0

Answer:

It's -7

Step-by-step explanation:

MariettaO [177]3 years ago

5 0

Answer:

-7

Step-by-step explanation:

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A square of an even number is always even.<br>True or false?<br>

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Answer:

Mostly likely it's True

Step-by-step explanation:

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1 year ago

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A circle cuts the x-axis at (4,0) and (14,0), and cuts the y-axis at (0,6) and (0,8). Find it's equation

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3 years ago

Please help me! Im making the first correct answer brainliest!

masha68 [24]

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Step-by-step explanation:

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2 years ago

To find the surface area of the pyramid, in square inches, Vikram wrote (33.2) (34.2) + 4 (one-half (34.2) (28.4)). What error d

madam [21]

Answer:

B. He used the wrong expression to represent the area of the base of the pyramid.

Step-by-step explanation:

Given

See attachment for pyramid

$Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4$

Required

Vikram's error

The surface area of a square pyramid is:

$Area = Base\ Area + 4 * Area \triangle$

Where

$Base\ Area = Length * Length$

$Base\ Area = 34.2 * 34.2$

$4 * Area \triangle = 4 * \frac{1}{2} * Base * Height$

$4 * Area \triangle = 4 * \frac{1}{2} * 34.2 * 28.4$

So:

$Area = Base\ Area + 4 * Area \triangle$

$Area = 34.2 * 34.2 + 4 * \frac{1}{2} * 34.2 * 28.4$

By comparing the calculated expression with

$Area = (33.2)(34.2) + 4 * \frac{1}{2} * 34.4 * 28.4$

Option (b) is correct

3 0

2 years ago

The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

Answer:

a) $P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b) $P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c) $P(A') = 1-P(A) =1-0.4=0.6$

d) $P(A \cup B) =0.4 +0.8-0.2 =1.0$

e) The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

a. P(A)

$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

Using the total law of probability we got:

$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

For this case $P(A \cap B) = P(c) =0.2$ , so if we replace we got:

$P(A \cup B) =0.4 +0.8-0.2 =1.0$

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

8 0

3 years ago