A mortgage is a <span>debt instrument</span>
Answer:
improvements to the building
Explanation:
As we know that the opportunity cost is the cost that gives the benefit in the altnernative when the other thing is sacrifice. Now the
As the second best choice is that there should be an improvement in the building so here the opportunity cost related to the purchase of a vehicle is building improvement
Hence, the same is to be considered
Answer:
$22,640
The explanation is shown below:-
Explanation:
The computation of cash flow from operating activities using the direct method is shown below:-
Direct method
Pizza International, Inc.
Statement of cash inflow
Cash flow from operating expenses
Cash received from customers $143,777
($143,951 - $174)
Cash Paid
To suppliers ($53,773)
($45,700 - $651 + $8,724)
To salaries and wages ($56,855)
For office expenses ($7,730)
($7,785 + $668 - $723)
For income tax expenses ($2,779)
($50 + $2,729)
Net cash inflow from operating
activities $22,640
It is mainly due to no depreciation expenses for cash products. Depreciation expenses do not contribute to cash outflows. Because of which company has reported large cash inflow from operations compared to near net loss.
Answer:
We'll start by putting into consideration, the large sample variance at the numerator.
Barron's Variance will be represented using 1 as the subscript.
i.e.
1 = $583 million
2 = $489 million
So,
0: 1²= 2²
: 1² ≠ 2²
=1² / 2²=
= $583 million² / $489 million²
= 583²/489²
= 1.42
Degrees of freedom 15 and 9
Using F table, area in tail is greater than 0.10.
Two-tail p-value is greater than .20
Exact p-value corresponding to F= 1.42 is .5874 (See F table)
p-value > .10
So,we do not reject 0.
We cannot conclude there is a statistically significant difference between the variances for the two companies.
Answer:
n = 150.06
Explanation:
Since the confidence c = 95% = 0.95
α = 1 - 0.95 = 0.05
z score of 0.025 is the same as the z score of 0.5 - 0.025 = 0.475
From the probability table, 
Also E = 0.08
Therefore the sample size n is given by:
n = 150.06
The sample must be at least 150.06 to be 95% sure that a point estimate will be within a distance of 0.08 from p
