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Varvara68 [4.7K]
3 years ago
9

You paint 1313 of a wall in 1414 hour. At that rate, how long will it take you to paint one wall?

Mathematics
1 answer:
Serhud [2]3 years ago
7 0
<span>You paint 1313 of a wall in 1414 hour.
Now we need to find the rate in order you to paint one wall.

1313 : 1414 = 1 : X
1414 = 1313 X
X = 1.08

So the rate per one wall is 1.08 hours.</span>
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The ratio of rainy days to non rainy days was 2 to 3. How many of the 30 days in April were rainy?
viktelen [127]
20 days were rainy.

2:3=x:30
2/3=x/30
x=20
3 0
3 years ago
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Help I’m in 5th 14 question
shutvik [7]
You would be right with 26 because the absolute value of -30 is 30 then you subtract 56-30 and get 26 which is the remaining temp you need to get to 56.
3 0
2 years ago
14% of 163<br> What is 14% of 163 estimated
Elina [12.6K]

Answer:

22.82

Step-by-step explanation:

it is about 22.82 when taken 14% away

3 0
3 years ago
On a fishing excursion, jeannie keeps 1/4 of the fish she catches and releases the remainder of the fish back into the lake. if
postnew [5]
To find 1/3 of 3/4 we divide the fraction by 3 which is equal to 1/4 or alternatively we can multiply the denominator by 3 which gives us 3/12 (1/4=3/12)
So 3/12 of the realesed fish are trout

To find 2/3 of 1/4 we need to first divide 1/4 by 3 which is equal to multiplying the denominator times 3 which gives us 1/12 and then we multiply by 2 which gives us 2/12
So 2/12 of the kept fish are trout

To find the total amount we add 2/12 and 3/12
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ANSWER:
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7 0
3 years ago
Can you guys help me out on this? I'm still learning sign, cosign, and tangent :)
Yakvenalex [24]

Answer:

\sin d = \frac{4}{7} ; \sin e = \frac{\sqrt{33} }{7}

\cos d = \frac{\sqrt{33} }{7} ; \cos e = \frac{4}{7}

\tan d = \frac{4}{\sqrt{33} } ; \tan e = \frac{\sqrt{33} }{4}

Step-by-step explanation:

For a right angled triangle with one of its angle α (alpha) :-

  • \sin \alpha = \frac{Side \: opposite \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \cos \alpha  = \frac{Side \: adjacent \: to \: \alpha }{Hypotenuse \: of \: the \: triangle}
  • \tan \alpha  = \frac{Side \: opposite \: to \: \alpha }{Side \: adjacent \: to \: \alpha }

__________________________________________________

According to the question ,

1) When α (alpha) = d

  • \sin d = \frac{4}{7}
  • \cos d = \frac{\sqrt{33} }{7}
  • \tan d = \frac{4}{\sqrt{33} }

2) When α (alpha) = e

  • \sin e = \frac{\sqrt{33} }{7}
  • \cos e = \frac{4}{7}
  • \tan e = \frac{\sqrt{33} }{4}

3 0
3 years ago
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