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Varvara68 [4.7K]
3 years ago
9

You paint 1313 of a wall in 1414 hour. At that rate, how long will it take you to paint one wall?

Mathematics
1 answer:
Serhud [2]3 years ago
7 0
<span>You paint 1313 of a wall in 1414 hour.
Now we need to find the rate in order you to paint one wall.

1313 : 1414 = 1 : X
1414 = 1313 X
X = 1.08

So the rate per one wall is 1.08 hours.</span>
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PLEASE HELP ME!
kotegsom [21]

Answer:

Bottom left graph

Step-by-step explanation:

We have to use what is called the zero-interval test [test point] in order to figure out which portion of the graph these inequalities share:

−2x + y ≤ 4 >> Original Standard Equation

+ 2x + 2x

_________

y ≤ 2x + 4 >> Slope-Intercept Equation

−2[0] + 0 ≤ 4

0 ≤ 4 ☑ [We shade the part of the graph that CONTAINS THE ORIGIN, which is the right side.]

\displaystyle y > x + 2 \\ \\ 0 ≯ 2[We shade the part of the graph that does not contain the origin, which is the left side.]

So, now that we got that all cleared up, we can tell that the graphs share a region in between each other and that they both have POSITIVE <em>RATE OF CHANGES</em> [<em>SLOPES</em>], therefore the bottom left graph matches what we want.

** By the way, you meant \displaystyle y > x + 2because this inequality in each graph is a <em>dashed</em><em> </em><em>line</em>. It is ALWAYS significant that you be very cautious about which inequalities to choose when graphing. Inequalities can really trip some people up, so once again, please be very careful.

I am joyous to assist you anytime.

7 0
3 years ago
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