All categories

3 years ago

Find the simple interest on a $3,219.00 principal, deposited for six years at a rate of 1.51%.

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

Answer:

s.i = P. T. R /100

= 3219 . 6 . 1.51 /100

= 29,164.14 / 100

= 291.6414

You might be interested in

Lots of point up for grabs

Burka [1]

Minus a from both sides
x-a=-2by²
times both sides by -1
a-x=2by²
divide both sides by 2b
$\frac{a-x}{2b}=y^2$
sqrt both sides
$y= \sqrt{\frac{a-x}{2b}}$

5 0

2 years ago

Read 2 more answers

Is 24/40 equal to four over five a true proportion

jeyben [28]

Answer:yes it is

hsyhsyxhsyxhsyhxysxys

4 0

3 years ago

Read 2 more answers

Find sin(B), cos(B) and tan(B) for the right triangle ABC shown. Please show your work below.

tangare [24]

Hello!

These are the following formulas to calculate sine, cosine, and tangent.

sin = opposite / hypotenuse

cos = adjacent / hypotenuse

tan = opposite / adjacent

To find sin(B), we need to find the side opposite of angle B, and the hypotenuse.

The opposite of angle B is 12, and the hypotenuse is 13.

sin(B) = 12/13

sin^-1(12/13) = 67.3801... This can be rounded to 67.38 degrees. (Tenths place: 67.4 degrees)

To find cos(B), we need to find the side adjacent of angle B, and the hypotenuse.

The adjacent side of angle B is 5, and the hypotenuse is 13.

cos(B) = 5/13

cos^-1(5/13) = 67.3801... It can be rounded to 67.38 degrees. Rounded to the tenths place is 67.4 degrees.

To find cos(B), we need to find the side adjacent and opposite of angle B.

The adjacent side of angle B is 5, and the opposite is 12.

tan(B) = (12/5)

tan^-1(12/5) = 67.3801... This can be rounded to about 67.38 degrees. Rounded to the tenths place is 67.4 degrees.

Therefore, the value of sin(B) is 67.38 degrees, the value of cos(B) is 67.38 degrees, and finally the value of tan(B) is 67.38 degrees.

7 0

3 years ago

Read 2 more answers

Triangle ABC is an isosceles right triangle. What is the measure of a base angle? °

MaRussiya [10]

90 degrees
cuz if you look closely it says isosceles RIGHT triangle
A right triangle has a measure of 90 degrees

8 0

3 years ago

Read 2 more answers

4n² +7n=0 what do I do if there is no part c?

Gnoma [55]

Answer:

Find the coefficients using ax^2 + bx + c = 0

a = 4

b = 7

c = 0

Make the coefficient equal 1. But how do we do that? Division.

4n² + 7n = 0

4/4n² + 7n/4 = 0/4

Simplify

= n² + 7/4n = 0

a = 1

b = 7/4

c = 0

Complete the square using b/2².

b = 7/4

(b/2)² = (7/4 ÷ 2)²

Use fraction rule.

7/4 ÷ 2² = 7/4² / 2²

square the numbers

7/4² / 2² = 49/16 ÷ 4

49/16 ÷ 4 = 49/16 × 1/4

49/16 × 1/4 = 49/64

Add to both sides of the equation using 49/64

b = 7/4

b/2 = 7/4 ÷ 2

simplify

b/2 = 7 ÷ (4 × 2)

simplify(arithmetic)

b/2 = 7/8

n² + 7/4n + 49/64 = 49/64

(n + 7/8)² = 49/64

Solve for the unknown x

$(n+\frac{7}{8})^2=\frac{49}{64}\\\sqrt{(n+\frac{7}{8})^2}=\sqrt{\frac{49}{64}}\\$

Next, cancel out the square on the left side.

$n+\frac{7}{8}=+/-\sqrt{\frac{49}{64}}$

Subtract 7/8 from both of the sides.

$n+\frac{7}{8}-\frac{7}{8}=-\frac{7}{8}+/-\sqrt{\frac{49}{64}}$

Simplify the left side.

$n=-\frac{7}{8}+/-\sqrt{\frac{49}{64}}\\n=-\frac{7}{8}+/-\frac{\sqrt{49}}{\sqrt{64}}\\n=-\frac{7}{8}+/-\frac{7}{8}\\n_1=0\\n_2=-\frac{7}{4}$

That wraps it up for this equation. Hope it helped!

3 0

1 year ago