PRU and STQ are not congruent because they aren’t the same size.
No, because they aren’t the same size.
<u>Step-by-step explanation:</u>
Both PRU and STQ triangles aren't in the same size, So it is not congruent. Triangles are congruent if two pairs of corresponding angles and a couple of inverse sides are equivalent in the two triangles.
If there are two sets of corresponding angles and a couple of comparing inverse sides that are not equal in measure, at that point the triangles are not congruent.
The Pythagorean's Theorem for our situation would look like this:

So let's call the short leg s, the long leg l and the hypotenuse h. It appears that all our measurements are based on the measurement of the short leg. The long leg is 4 more than twice the short leg, so that expression is l=2s+4; the hypotenuse measure is 6 more than twice the short leg, so that expression is h=2s+6. And the short leg is just s. Now we can rewrite our formula accordingly:

And of course we have to expand. Doing that will leave us with

Combining like terms we have

Our job now is to get everything on one side of the equals sign and solve for s

That is now a second degree polynomial, a quadratic to be exact, and it can be factored several different ways. The easiest is to figure what 2 numbers add to be -8 and multiply to be -20. Those numbers would be 10 and -2. Since we are figuring out the length of the sides, AND we know that the two things in math that will never EVER be negative are time and distance/length, -2 is not an option. That means that the short side, s, measures 10. The longer side, 2s+4, measures 2(10)+4 which is 24, and the hypotenuse, 2s+6, measures 2(10)+6 which is 26. So there you go!
Yes, remember this 4 or less let it rest, 5 or more let it soar.
we are given with the set of data containing the elements listed above and is asked to find out the standard deviation of the data. SD is used to determine the distance between the points to the best fit line gained from the data. The formula to be followed is the square root of the summation of (x-mean) over n-1. sd is equal to <span>5.13.</span>