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DIA [1.3K]
2 years ago
11

Seven and two eighths minus five and one eighth equals?

Computers and Technology
1 answer:
lakkis [162]2 years ago
4 0

Answer: 2.125

Explanation

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true

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Name two features that would be useful to potential customers
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Respond the subject "Who are you and What your business represents?" as interestingly and compellingly as feasible. This involves recording administration bios that state your expertise, times of struggle and various different qualities or details that may make you special from others.

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When designing a slide for presentation, it is best to include as much information as possible on every slide. True Or False
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Below is a list of 32-bit memory address references, given as word addresses.
Maru [420]

For a direct mapped cache the general rule is: first figure out the bits of the offset (the right-most bits of the address), then figure out the bits of the index (the next-to right-most address bits), and then the tag is everything left over (on the left side).

One way to think of a direct mapped cache is as a table with rows and columns. The index tells you what row to look at, then you compare the tag for that row, and if it matches, the offsettells you which column to use. (Note that the order you use the parts: index/tag/offset, is different than the order in which you figure out which bits are which: offset/index/tag.)

So in part (a) The block size is 1 word, so you need 0 offset bits (because <span><span><span>20</span>=1</span><span><span>20</span>=1</span></span>). You have 16 blocks, so you need 4 index bits to give 16 different indices (because <span><span><span>24</span>=16</span><span><span>24</span>=16</span></span>). That leaves you with the remaining 28 bits for the tag. You seem to have gotten this mostly right (except for the rows for "180" and "43" where you seem to have missed a few bits, and the row for "181" where you interchanged some bits when converting to binary, I think). You are correct that everything is a miss.

For part (b) The block size is 2 words, so you need 1 offset bit (because <span><span><span>21</span>=2</span><span><span>21</span>=2</span></span>). You have 8 blocks, so you need 3 index bits to give 8 different row indices (because <span><span><span>23</span>=8</span><span><span>23</span>=8</span></span>). That leaves you with the remaining 28 bits for the tag. Again you got it mostly right except for the rows for "180" and "43" and "181". (Which then will change some of the hits and misses.)

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Three of these simple machines are similar to one another. Choose the one that does not belong with this group. pulley, wheel an
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