Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
Answer:
I believe its D.
Rational Only
Step-by-step explanation:
Okay, I will give you the building blocks for solving this equation.
Now something you will need to remember is that a triangle will always add up to 180 degrees.
We can use y as that one unknown side in the triangle.
Knowing this, we can say (9x+16) + (6x+15) + y = 180
Then we can combine like terms like so : 15x+31+y = 180
There are two variables though. So we need more information.
Well, turns out we have the exterior angle of a straight line and the angle measures of a straight line must equal 180. We can now use (19x+3) + y = 180.
With both of these equations, you can now solve and find both of the angles
Answer:
A reflection over the <em>y</em>-axis.
F equals negative forty. Hope this helps!!
