3 years ago

What is the equation of the line that passes through the points (2,-1) and (6,1)?

1 answer:

3 0

The answer is y=1/2x-2

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Afina-wow [57]

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3 years ago

olga_2 [115]

Answer: (x+7)^2 + (y-4)^2 = 121 or (x+7)^2 + (y-4)^2 = 11^2

Step-by-step explanation:

Equation of the circle is:

$(x-h)^2+(y-k)^2=r^2$ , which is the center $(h,k)$ and the radius $r^2$

-Place the center (-7,4) and radius 11 onto that equation:

$(x+7)^2+(y-4)^2=121$ (if simplified radius needed)

$(x+7)^2(y-4)^2=11^2$

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3 years ago

Cloud [144]

I think it’s 14/-28 which simplifies to 7/-14 which then goes to 1/-2. i hope that helped!

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nekit [7.7K]

Factors of 54: 1, 2, 3, 6, 9, 18, 27, 54.

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Burka [1]

I think C but I’m not sure

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3 years ago