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3 years ago

:)

Mathematics

1 answer:

vitfil [10]3 years ago

6 0

Answer:

45-(-15)

430-(-180)

11,560-(-185)

Step-by-step explanation:

just add the two numbers together for diffrence.

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Please help me Im almost done

SSSSS [86.1K]

Answer:

$\mathsf {x = 76}$

Step-by-step explanation:

The given pair of angles lie on a line, hence they are classified as linear angles. They possess the property by which their sum is equal to 180°.

$\textsf {Solving :}$

$\implies \mathsf {x + 17 + 87 = 180}$

$\implies \mathsf {x + 104 = 180}$

$\implies \mathsf {x = 180 - 104}$

$\implies \mathsf {x = 76}$

8 0

2 years ago

Find the missing side length in the following triangle.

Ilya [14]

169 because you have to add the angles from the inside and the firat angke is 90

6 0

3 years ago

Question 5 of 20

Dmitry_Shevchenko [17]

I’m going to say B I could be wrong

3 0

3 years ago

The graph below represents the solution set of which inequality?

natulia [17]

Answer:

option: B ( $x^2+2x-8$ ) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

On solving the first inequality we have:

$x^2-2x-8$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8$

⇒ $x(x-4)+2(x-4)=0$

⇒ $(x+2)(x-4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x+2>0$ and $x-4$

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

$x+2$ and $x-4>0$

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

We are given the second inequality as:

$x^2+2x-8$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8$

⇒ $x(x+4)-2(x+4)$

⇒ $(x-2)(x+4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x-2>0$ and $x+4$

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

$x-2$ and $x+4>0$

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

$x^2-2x-8>0$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8>0$

⇒ $x(x-4)+2(x-4)>0$

⇒ $(x-4)(x+2)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x+2>0$ and $x-4>0$

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

$x+2$ and $x-4$

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

$x^2+2x-8>0$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8>0$

⇒ $x(x+4)-2(x+4)>0$

⇒ $(x-2)(X+4)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x-2$ and $x+4$

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

$x-2>0$ and $x+4>0$

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.

5 0

3 years ago

Braden has already taken 1 page of notes on his own, and he will take 2 pages during each hour of class. Write an equation that

beks73 [17]

Answer:

2h=2p

1h=1p

Step-by-step explanation:

7 0

3 years ago