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11Alexandr11 [23.1K]
3 years ago
10

What is the vertex of the function?

Mathematics
1 answer:
Romashka [77]3 years ago
8 0

Answer:

  (4, -25)

Step-by-step explanation:

One way to answer this is to put the equation into vertex form.

  f(x)= x^2 -8x -9 . . . . . given

Add and subtract the square of half the x-coefficient:

  f(x) = x^2 -8x +(-8/2)^2 -9 -(-8/2)^2

  f(x) = x^2 -8x +16 -25

  f(x) = (x -4)^2 -25

Comparing this to the vertex form of a quadratic:

  f(x) = a(x -h)^2 +k

we find that (h, k) = (4, -25). This is the vertex.

_____

<em>Alternate solution</em>

The line of symmetry for ...

  f(x) = ax^2 +bx +c

is given by x = -b/(2a). For your given quadratic that line is ...

  x = -(-8)/(2(1)) = 4

Evaluating f(4) gives the y-coordinate:

  f(4) = 4^2 -8·4 -9 = -25

The vertex is (x, y) = (4, -25).

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A carpenter wants to cut a board 16 1/2 feet in length into 1 7/8 feet pieces. How many pieces can be cut from the board? The ca
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<h3>Answer:</h3>
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<h3>Explanation:</h3>

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<em>Comment on arithmetic with fractions</em>

This problem is easier if you <em>convert the mixed numbers to improper fractions</em>. This is done by expressing the integer as a number of fractional parts, then adding the fraction part of the mixed number:

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... 132/15 = 44/5 = 8 4/5

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