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Andrej [43]
2 years ago
13

6.

Mathematics
1 answer:
Eva8 [605]2 years ago
4 0

Answer:

17-3-5=9???

Step-by-step explanation:

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Write the equation in general form.<br> x^2 +6x = -2
Anastaziya [24]

Answer:

x^2 + 6x + 2 = 0

Step-by-step explanation:

Just add 2 to both sides, obtaining x^2 + 6x + 2 = 0; this is in "general form" for a quadratic equation.

3 0
3 years ago
Can someone send the steps to solve​
Paladinen [302]

Answer:

151 degrees

Step-by-step explanation:

6 0
3 years ago
The admission fee to an amusement park is $28. It costs an additional p dollars to rent a locker to hold your belongings. The to
mina [271]

The overall equation we can generate from the problem is:

C = (28 + p) * x

where C is the total cost, p is the payment for the locker, and x the number of people

We can calculate for p:

180 = (28 + p) * 5

28 + p = 36

p = 8

 

Therefore the cost of one person, x = 1:

C = (28 + 8) * 1

C = $36

 

Answer:

<span>$36</span>

3 0
3 years ago
Looking at the two quadratic functions below (1 &amp; 2), answer the following questions.
algol [13]
Part A:

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that parabola (2) is stretched horizontally by a factor of 13 which is greater than 1. This means that parabola (2) is further away from the x-axis than parabola (1). (i.e. parabola (2) is more 'vertical' than parabola (1).

Therefore, parabola (1) is wider than parabola (2).



Part B:

A parabola open up when the coefficient of the quadratic term (the squared term) is positive and opens down when the coefficient of the quadratic term is negative.

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that the coefficient of the quadratic term is positive for parabola (2) and negative for parabola (1), therefore, the parabola that will open down is parabola (1).



Part C:

For any function, f(x), the graph of the function is moved p places to the left when p is added to x (i.e. f(x + p)) and moves p places to the right when p is subtracted from x (i.e. f(x - p)).

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that in parabola (1), 12 is added to x, which means that the graph of the parent function is shifted 12 places to the left while in parabola (2), 4 is subtracted from x, which means that the graph of the parent function is shifted 4 places to the right.

Therefore, the parabola that would be furthest left on the x-axis is parabola (1).



Part D:

For any function, f(x), the graph of the function is moved q places up when q is added to the function (i.e. f(x) + q) and moves q places down when q is subtracted from the function (i.e. f(x) - q).

Given parabola (1) to be f(x) =-(x+12)^2 -6, and parabola (2) to be f(x)=13(x-4)^2+1

Notice that in parabola (2), 1 is added to the function, which means that the graph of the parent function is shifted 1 place up while in parabola (1), 6 is subtracted from the function, which means that the graph of the parent function is shifted 6 places down.

Therefore, the parabola that would be highest on the y-axis is parabola (2).
7 0
3 years ago
Find the area of this trapezoid. Be sure to include the correct unit in your answer.
Sedaia [141]

Answer:

88 sq.in

Step-by-step explanation:

<u>Area of trapezoid = 1/2 (b1 +b2) x h</u>

<u>In this figure:</u>

b1 = 18 in, b2 = 4 in, h = 8 in

<u>So:</u>

A = 1/2 (18 + 4) x 8

A = 1/2 (22) x 8

A = 11 x 8

A = <u>88 sq.in</u>

5 0
2 years ago
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