Question

Suppose that the concentration of Na outside the cell is 100 and inside the cell is 100 mmol/liter. The Nernst equation at 20oC is: You set the membrane voltage at 58 millivolts using a voltage clamp, and measure membrane current. If Na is the only ion crossing the membrane, you would expect to see:

Answer 1

Answer:

0 current

Explanation:

Given that:

The concentration of Na inside the cell is 100 mmol/liter

The concentration of Na outside the cell is 100 mmol/liter

where;

z(valence of the ionic species for Na⁺ ) = +1, and the membrane voltage is 58 millivolt

Therefore;

$E_{ion} = \dfrac{58}{z} \times log _{10} \bigg (\dfrac{[ion]_{out}}{[ion]_{in}}\bigg)$

$E_{ion} = \dfrac{58}{1} \times log _{10} \bigg (\dfrac{100}{100}\bigg)$

$E_{ion} =58 \times log _{10} \bigg (1\bigg)$

$E_{ion} = 58 \times 0$

$\mathbf{E_{ion} =0}$