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3 years ago

The vertex angle of an isosceles triangle measures ( 6x -9)° and one of the base angles measures (4x)°. What is the value of x?

Mathematics

1 answer:

Gnom [1K]3 years ago

5 0

Answer:

x = 13.5

Step-by-step explanation:

We know that base angles of an isosceles triangle are equal. The base angles of the triangle are (4x)° each. The vertex angle of the traingle is (6x-9)°. So according to angle sum property of triangle,

$6x - 9 + 4x + 4x = 180$

$= > 6x - 9 + 8x = 180$

$= > 14x - 9 = 180$

$= > 14x = 180 + 9 = 189$

$= > x = \frac{189}{14} = 13.5$

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Use a matrix to solve the system:

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(2.83 , 1 , 4)

Step-by-step explanation:

$2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\$

Rewrite these equations in matrix form

$\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\$

we can write it like this,

$AX=B\\X=A^{-1}B$

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

$A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right] \\$

now multiply the matrix with B

$X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\$