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storchak [24]
2 years ago
9

How far does Miss Ireland live from Mrs. Brown if

Mathematics
1 answer:
frozen [14]2 years ago
8 0

90 miles driving at 45 mph for 2 hours

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A line passes through the point, (−8,7) and has a slope of −5/4. Please help...
o-na [289]

Answer:

5x + 4y + 12 = 0

Step-by-step explanation:

Start with the point-slope equation of a straight line:  y - k = m(x -  h):

Here we are given the point (h, k):  (-8, 7) and the slope m = -5/4.  Inserting this info into the equation give above, we get:        y - 7 = (-5/4)(x + 8).

We must put this equation into "standard form" Ax + By + C = 0.

Multiply all three terms by 4 to remove fractions:  4y - 28 = -5(x + 8), or

4y - 28 + 5x + 40 = 0

Rearranging these terms, we get 5x + 4y + 12 = 0, which is the desired equation in standard form.

8 0
3 years ago
Please help me with this Question
lutik1710 [3]
I did a good time at work but I got to get it done I got my car back and I’m gonna was a great
4 0
2 years ago
Tommy's mom gave him $50 for cutting their grass. He used the money to buy a game for $15.75 and two snacks that cost $1.50 each
Alborosie

Answer:

a = $17.25

Step-by-step explanation:

let the money spend on the necklace be a

we have

15.75 +1.5*2 +a + 14 = 50

-> a = 50 -15.75 -3-14

-> a = $17.25

8 0
3 years ago
A student walk 60m on a bearing
Katena32 [7]

Answer:

d = 234.6 m

Step-by-step explanation:

You can consider a system of coordinates with its origin at the beginning of the walk of the student.

When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:

x_1=60cos28\°=52.97m\\\\y_1=60sin28\°=28.16m

she is at the coordinates (52.97 , 28.16)m.

Next, when she walks 180m to the east, her coordinates are:

(52.97+180 , 28.16)m = (232.97 , 28.16)m

To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:

d=\sqrt{(x-x_o)^2+(y-y_o)^2}\\\\x=232.97\\\\x_o=0\\\\y=28.16\\\\y_o=0\\\\d=\sqrt{(232.97-0)^2+(28.16-0)^2}m=234.6m

The displacement of the student on her complete trajectory was of 234.6m

8 0
3 years ago
Help help math math math
adelina 88 [10]

Answer:

113

Step-by-step explanation:

The supplement of angle 3 is congruent to 67, because they are corresponding angles. After you subtract the supplement from 180, you should get angle 3

180-67=113

8 0
2 years ago
Read 2 more answers
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