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statuscvo [17]
3 years ago
9

I need some help solving two equations on my Algebra 1 homework

Mathematics
1 answer:
EleoNora [17]3 years ago
5 0
1. y < -x - 5......(-3,-4)
2. 5x - 3y < = 15.....all of ur answers satisfy this inequality
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$56,820 rounded to the nearest dollar
Alex_Xolod [135]
Well, if that is a comma in the number, it is already rounded. If the comma is supposed to be a decimal, the answer would be $57.
6 0
3 years ago
Find the coordinates of the midpoint of a segment having the given endpoints.
inysia [295]

Answer:

A. (1.55, 2)

Step-by-step explanation:

The formula to apply when finding the midpoint of a segment where the coordinates of the end points are given is;

midpoint=(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )

where (x₁,y₁) and (x₂,y₂) are the coordinates of the end points

Given;

x₁= -0.4 ,y₁=2.5,  x₂=3.5, y₂=1.5 then applying the formula for midpoint

=(\frac{-0.4+3.5}{2} ,\frac{2.5+1.5}{2} )\\\\\\=(\frac{3.1}{2} ,\frac{4.0}{2} )\\\\\\=(1.55,2.0)

3 0
3 years ago
The following table shows the number of hours some students in two universities spend reading each week:
AleksandrR [38]
They do not appear to be symmectric. they seem to line up well
4 0
3 years ago
A circle with area 9 pi, has sector with central angle of 17/9 pi radians
mr_godi [17]

Answer:

The area of the sector is 17/2 π

Step-by-step explanation:

pi = π

To solve this problem we first have to find the fraction that corresponds to this angle of the total, for this we must divide the angle that they give us by 2π radians, since that is the angle of a circle

(17π/9 rad) / (2π rad) = 17/18

Now we multiply the area of ​​the circle by this fraction and we will obtain the area of ​​the sector that we want

9π * 17/18 = 17/2 π

The area of the sector is 17/2 π

3 0
3 years ago
Write the number of permutations in factorial form. Then simplify. J K L M N O P
guajiro [1.7K]

Answer:

The number of permutations of the group of letters given (J, K, L, M, N, O and P) is 7! = 7 . 6 . 5 . 4 . 3 . 2 . 1 = 5,040.

Step-by-step explanation:

The number of permutations without repetition is the number of possible sequences that can occur if we take the letters one by one and is calculated with the factorial of the total number of letters in the group.

Before starting we have 7 possibilities, one for each letter. Once the first letter is chosen randomly, we will have 6 possibilities, after taking the third letter we will have 5 possibilities, and so on.

In total the total number of possibilities to obtain the 7 letters in a certain order are 7 by 6 by 5 by 4 by 3 by 2 by 1, sayed in other words factorial of 7 (7!). The result of the multiplication gives 5,040.

In short we can get the seven letters in 5,040 different sequences.

7 0
3 years ago
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