Answer:1)5x^2-11x
2) x^2-3x
Step-by-step explanation:
1)(f+g)(x)
f(x)=3x-7
g(x)= 2x-4
[(3x-7)+(2x-4)](x)
3x^2-7x+2x6^2-4x
=<u>5x^2-11x</u>
2) (f-g)(x)
[(3x-7)-(2x-4)](x)
(3x-7-2x+4)(x)
3x^2-7x-2x^2+4x
x^2-3x
<span><span> 17
</span><span>2 35
</span> 2
<span> 15
</span><span> 14
</span><span> 1
The remainder ends up to be 1. So it is 17.5. All you need to do, is to look for LCM in 35 and 2. </span></span>
Answer:
i think linear
Step-by-step explanation:
let me know if this is wrong
Answer:
627
Step-by-step explanation:
We have to find the sum of the given expression which is:
We start adding from right hand digits
we will first add right most digit of 362 and 265
which is 2+5=7
Now, the previous right most digit from both the numbers which is 6+6=12
Now, since, we are getting a two digit number we will consider right digit from the resultant which is 2 and 1 will be taken as carry to the next two digits that are to be added
Now, we will ad next two digits that are left which is 3+2=5 and 1 carry will be added
Hence,6
Final result is written as in sequence they were added which is 627
Y = 4x - 3 - x^2
now sub that in for y in the other equation
x + y = 1
x + 4x - 3 - x^2 = 1
-x^2 + 5x - 4 = 0
(-x + 1)(x - 4) = 0
-x + 1 = 0 y = 4x - 3 - x^2
-x = -1 y = 4(1) - 3 - 1^2
x = 1 y = 4 - 3 - 1 = 0
x - 4 = 0 y = 4x - 3 - x^2
x = 4 y = 4(4) - 3 - 4^2
y = 16 - 3 - 16
y = -3
points that satisfy this are : (1,0) and (4,-3)
