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Ket [755]
2 years ago
5

1. Evaluate each expression without using a calculator. (a)

mula1" title="(-3)^{4}" alt="(-3)^{4}" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Rufina [12.5K]2 years ago
5 0

The result of the exponential expression is 81

<h3>Indices expressions</h3>

Indices are written in term of exponents

According to the expoenent law of indices

a^4 = a * a * a * a

Given the expression

(-3)^4

This means the product of -3 in four places. Mathematically

(-3)^4 = -3 * -3 * -3 * -3
(-3)^4 = 9 * 9
(-3)^4 = 81

Hence the result of the exponential expression is 81

Learn more on exponents here: brainly.com/question/11975096

You might be interested in
What greatest three digit number whose hundreds is two less than its ones digit
kodGreya [7K]

Answer:

799

Step-by-step explanation:

Let x = the hundreds digit

Let y = the ones digit

x = y-2

We want to maximize x and y.  The both have to be single digit numbers

Rewriting this

x+2 =y

The largest x can be is 7 if y is a single digit

x is 7 and y is 9

We can pick the tens digit.  Make it as big as possible to make out number as large as possible

799

4 0
3 years ago
Identify the range of the function shown in the graph
eduard

Answer:

The answer is B.

6 0
2 years ago
Find the sum 7a/a+5 + a/a-2
IRINA_888 [86]

\dfrac{7a}{a+5}+\dfrac{a}{a-2} \\\dfrac{7a(a-2)+a(a+5)}{(a+5)(a-2)} \\\boxed{\dfrac{a(8a-9)}{(a+5)(a-2)}}

Hope this helps.

8 0
3 years ago
The height h (in feet) of an object dropped from a ledge after x seconds can be modeled by h(x)=−16x2+36 . The object is dropped
kakasveta [241]

Check the picture below.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(t) = -16t^2+v_ot+h_o \quad \begin{cases} v_o=\textit{initial velocity}&\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&\\ \qquad \textit{at "t" seconds} \end{cases}

so the object hits the ground when h(x) = 0, hmmm how long did it take to hit the ground the first time anyway?

\bf h(x)=-16x^2+36\implies \stackrel{h(x)}{0}=-16x^2+36\implies 16x^2=36 \\\\\\ x^2=\cfrac{36}{16}\implies x^2 = \cfrac{9}{4}\implies x=\sqrt{\cfrac{9}{4}}\implies x=\cfrac{\sqrt{9}}{\sqrt{4}}\implies x = \cfrac{3}{2}~~\textit{seconds}

now, we know the 2nd time around it hit the ground, h(x) = 0, but it took less time, it took 0.5 or 1/2 second less, well, the first time it took 3/2, if we subtract 1/2 from it, we get 3/2 - 1/2  = 2/2 = 1, so it took only 1 second this time then, meaning x = 1.

\bf ~~~~~~\textit{initial velocity in feet} \\\\ h(x) = -16x^2+v_ox+h_o \quad \begin{cases} v_o=\textit{initial velocity}&0\\ \qquad \textit{of the object}\\ h_o=\textit{initial height}&\\ \qquad \textit{of the object}\\ h=\textit{object's height}&0\\ \qquad \textit{at "t" seconds}\\ x=\textit{seconds}&1 \end{cases} \\\\\\ 0=-16(1)^2+0x+h_o\implies 0=-16+h_o\implies 16=h_o \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = -16x^2+16~\hfill

quick info:

in case you're wondering what's that pesky -16x² doing there, is gravity's pull in ft/s².

4 0
3 years ago
Rene made a 90 % on her math test. If she answered 20 problems correctly , how many problems were on the test ?
MakcuM [25]

Answer:

Rene made = 90 on her math test

If she answer =20problems correctly

we know,

how many problem were there = ?

there where = 90-20

= 70

There where 70 problems

8 0
2 years ago
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