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Iteru [2.4K]
3 years ago
6

Is each line parallel, perpendicular, or neither parallel nor perpendicular to a line whose slope is −34?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
8 0

Given:

The slope of a line is -\dfrac{3}{4}.

To find:

The lines in the options are parallel, perpendicular or neither parallel nor perpendicular to the given line.

Solution:

We know that the slopes of parallel lines are equal.

The slope of line Q and the slope of given line are same, i.e., -\dfrac{3}{4}. So, the line Q is parallel to the given line.

The slope of a perpendicular line is the opposite reciprocal of the slope of the line because the product of slopes of two perpendicular lines is -1.

The slope of a line is -\dfrac{3}{4}. It means the slope of the perpendicular line must be \dfrac{4}{3}. So, the line N is perpendicular to the given line.

The slopes of line M and P are neither equal to the slope of the given line nor opposite reciprocal of the slope of the line.

Therefore, the lines M and P are neither parallel nor perpendicular.

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A pickup truck carrying 10 to the 3rd power identical bricks weighs 6,755 pounds. If the empty truck weighs 6,240 pounds, what i
Aleks04 [339]

Answer:

The answer is that each brick weights .515 pounds.

Step-by-step explanation:

10 to the 3rd power is 10^3 = 1000 bricks.

The weight of the full truck minus the weight of the empty truck is the weight of the bricks:

6755 - 6240 = 515 pounds of bricks

Pounds per brick:

515 / 1000 = .515 pounds per brick.

Hope this helps! Have a great day!

5 0
3 years ago
Y= 2x-8,what is the slope and the y-intercept
Natalija [7]
Hi is the answer so this makes it okay to do thing when you have it
8 0
3 years ago
5x7/8 less than or greater
Pavel [41]
5x7= 35
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5 0
3 years ago
Read 2 more answers
Write the equation in standard form for the circle with center (0, – 10) and radius 6.
Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: (x-h)^2+(y-k)^2=r^2

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36

So, equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x-y%3D4%5C%5Cy-x%3D4" id="TexFormula1" title="2x-y=4\\y-x=4" alt="2x-y=4\\y-x=4" align="absmi
Flura [38]
Here is the answer. Hope this helps!

5 0
1 year ago
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