D = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64
The sum will be:
sigma(i = 1 to infinity, 30*(2/5)^i)
->
Which is equal to 30/(3/5) = 50
Answer:
Step-by-step explanation:
if we're going by a 24 pack of soda, 3/8 would be 9 sodas while 4/12 is a third, which would be 8 sodas
Rewriting the left-hand side as follows,
