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photoshop1234 [79]
3 years ago
7

What is 7/100 as a percentage

Mathematics
2 answers:
UkoKoshka [18]3 years ago
8 0
7/100 is a fraction of seven out of 100.  so if you turn it into a percentage, it is 7%

:)
maria [59]3 years ago
7 0
The answer is 7%, since you would divide 7/100. 
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A rectangle has an area of x^2 -6x -7 and a width of x-7 what’s the length
iogann1982 [59]

Answer:

x+1

Step-by-step explanation:

We know that x^2 -6x-7 is the product of two binomials.

We can solve this two ways, but the easier way is to simply factor rather than divide the area by width.

Two numbers, one of which being -7 allows for the sum of -6 and the product of -7.

Using this information, we can identify the other number is 1, so the length is x+1.

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QUICKK ANSWERR (will mark brainlist)
atroni [7]

Answer:

Jessie sold x DVDs for $<u>3</u> each and then sold a board game for $<u>12</u>. Jessie made (select) $27 in her sales. How many DVDs did she sell?

She sold 5 DVDs

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3x+12=27

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3 years ago
The table lists students in an international summer school and the countries they come from.
ruslelena [56]

Answer: No

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
One leg of a right triangle has length 7. The lengths of the other two sides are whole numbers. The length of the other leg is _
Gekata [30.6K]
It should be 7, 24 and 25
8 0
3 years ago
The probability of flu symptoms for a person not receiving any treatment is 0.038. In a clinical trial of a common drug used to
alexgriva [62]

Answer:

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

Step-by-step explanation:

I am going to use the normal approximation to the binomial to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 1164, p = 0.038

So

\mu = E(X) = np = 1164*0.038 = 44.232

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = 6.5231

Estimate the probability that at least 47 people experience flu symptoms.

Using continuity correction, this is P(X \geq 47 - 0.5) = P(X \geq 46.5), which is 1 subtracted by the pvalue of Z when X = 46.5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{46.5 - 44.232}{6.5231}

Z = 0.35

Z = 0.35 has a 0.6368

1 - 0.6368 = 0.3632

36.32% probability that at least 47 people experience flu symptoms. This is not an unlikely event, so this suggests that flu symptoms are not an adverse reaction to the drug.

6 0
2 years ago
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