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Pavel [41]
3 years ago
15

before the recent house bonding there were 3212 houses in Fulton country now there are 3979 houses. How many houses did develope

rs build during the house boom
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
6 0

Answer:

767 houses

Step-by-step explanation:

Initially there are 3212 houses in the city.

After the boom there are 3979 houses in the city.(due to boom there is an increase in the number of houses).

The number of houses developed by the developers is the difference between the number of houses before and after the boom.

The number of houses developed=3979-3212=767 houses

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the popilation of Detroit, Michigan was 951,300 in. Detroit has been experiencing a population decile of 1.4% per year since 200
timama [110]
This can be solve using the formula
F = P(1 - i)^nwhere F is the future populationP is the initial populationi is the percent population declinen is the number of years
F = 951,300 ( 1 - 0.014)^5F = 886,548 will be the population in 2005
8 0
3 years ago
Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete
icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Fleet of 17 means that N = 17

4 are carrying nucleas weapons, which means that k = 4

9 are destroyed, which means that n = 9

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

P(X > 1) = 1 - P(X \leq 1)

In which

P(X \leq 1) = P(X = 0) + P(X = 1)

So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294

P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118

Then

P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412

P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0
3 years ago
adam wants to compare the fractions 3/12,1/6, and 1/3.he wants to order them from least to greatest and rewrite them so they all
Digiron [165]
3/12 ; 1/6 ; 1/3

Adam must first get the least common multiple of each denominator.

12 : 12, 24, 36
  6 :  6, 12, 18
  3 :  3, 6, 9, 12

12 is the least common denominator. 

We, then, multiply each denominator by a number that will produce 12.

12 x 1 = 12
6 x 2 = 12
3 x 4 = 12

Each number multiplied to the denominator must be the number used to multiply each numerator.

3/12 * 1/1 = 3/12
1/6 * 2/2 =   2/12
1/3 * 4/4 =   4/12

Since they now share a common denominator, the numerator will become the basis of the fraction's value. The greater the numerator, the greater the fraction's value.

Fractions in order from least to greatest = 2/12 ; 3/12 ; 4/12

Substitute each fraction with its original fraction:
2/12 ⇒ 1/6   : least

3/12 ⇒ 3/12 : middle
4/12 ⇒ 1/3   : greatest
7 0
3 years ago
The sum of squares of two consecutive odd numbers is 514 find the numbers ​
amid [387]

Correct Question : The sum of squares of two consecutive positive odd numbers is 514. Find the numbers.

\rule{130}1

Solution :

Let the two consecutive positive odd numbers be x and (x + 2)

\rule{130}1

☯ \underline{\boldsymbol{According\: to \:the\: Question\:now :}}

:\implies\sf x^2 + (x + 2)^{2} = 514 \\\\\\:\implies\sf x^2 + x^2 + 4x + 4 = 514\\\\\\:\implies\sf 2x^2 + 4x + 4 = 514 \\\\\\:\implies\sf 2x^2 + 4x = 514 - 4\\\\\\:\implies\sf 2x^2 + 4x = 510 \\\\\\:\implies\sf 2x^2 + 4x - 510 = 0\\\\\\:\implies\sf x^2 + 2x - 255 = 0 \:\:\:\:\:\Bigg\lgroup \bf{Dividing\:by\:2}\Bigg\rgroup\\\\\\:\implies\sf x^2 + 17x - 15x - 255 = 0\\\\\\:\implies\sf x(x + 17) - 15(x + 17) = 0\\\\\\:\implies\sf (x + 17) (x - 15)\\\\\\:\implies\sf x = - 17\:or\:x = 15\\\\\\:\implies\underline{\boxed {\sf x = 15}}\:\:\:\:\:\Bigg\lgroup \bf{Positive\:odd\: number}\Bigg\rgroup

When,

\bullet\: \textsf {x = } \textbf {15}

\bullet\: \sf x + 2 = 15 + 2 =\textbf{ 17}

\therefore\:\underline{\textsf{The required positive integer is \textbf{15 and 17}}}.

5 0
3 years ago
Which is an equation of the line that passes through the point(2,3) and has a slope of 1/3
777dan777 [17]
Y = 1/3x + b
Plug in the point
3 = 1/3(2) + b
3 = 2/3 + b, b = 7/3
Solution: y = 1/3x + 7/3
7 0
3 years ago
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