It's 1/3 which can = 0.3333...
To solve this, we have to find the volume of the cylinder first. The formula to be used is
Given:V= ?r= 6cmh= 10cm
Solution:
V= (3.14)(6cm)
x 10cmV= (3.14)(
) x 10cmV= (
) x 10cmV= 1130.4cm^3
Finding the volume of the cylinder, we can now solve what the weight of the oil is. Using the formula of density, Density = mass/volume, we can derive a formula to get the weight.
Given:Density = 0.857 gm/cm^3Volume = 1130.4 cm^3
Solution:weight = density x volumew= (0.857 gm/cm^3) (1130.4cm^3)w= 968.7528 gm
The weight of the oil is 968.75 gm.
Answer:
FOIL
Step-by-step explanation:
First
Outside
Inside
Last
If you dont fully understand look at the attachment
Answer:
Step-by-step explanation:
We are asked to divide our given fraction: .
We will simplify our division problem using rules of exponents.
Using product rule of exponents we can write:
Substituting these values in our division problem we will get,
Using power rule of exponents we will get,
Using quotient rule of exponent we will get,
Using product rule of exponents we will get,
Upon canceling out we will get,
Using power rule of exponents we will get,
Therefore, our resulting quotient will be .
1)B -26-27x
steps :distribute ,-9 times 3 =-27 , -9 times 3x = -27x , now combine like terms :you have a 1 and a -27 ,1-27=-26,and you left with -27
2)D 11-49x
steps :distribute , positive 7 times 1= 7 and then positive 7 times negative 7x =-49, now combine like terms ,since you have a positive 4 combine it with positive 7 which is 11 and finally put it together with -49x which it would look like 11-49x