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ArbitrLikvidat [17]
3 years ago
6

Somebody can help me plz? It seems easy for y’all but not for me haha

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

I'll say 25 but not too sure!

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What is the solution to the system of equations?<br> y = -5x + 3<br> y = 1
Gekata [30.6K]

9514 1404 393

Answer:

  (x, y) = (2/5, 1)

Step-by-step explanation:

Substitute for y and solve for x.

  1 = -5x +3

  -2 = -5x . . . . . . subtract 3

  2/5 = x . . . . . . divide by -5

The solution is (x, y) = (2/5, 1).

4 0
3 years ago
A rental company charges a flat fee of x dollars for floor sander rental plus Y dollars per hour for the rental. One customer re
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$15 is the original purchase. $12 and hour.



15+12y
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3 years ago
2(x - 4) = 2(-2x + 1)
natita [175]

Answer:

?

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the area of the two rectangles shown below?
DedPeter [7]

Answers are in bold.

<em><u>For the first one:</u></em>

The total area of both shaded and unshaded portions is equal to 3x(4x+7), which simplifies to 12x^2}+21x. The area of the middle white portion is (5x)(2x), which simplifies to 10x^2. To find the area of the shaded portion, we do 12x^2}+21x - 10x^2. Combining like terms, we get 2x^2+21x as our expression for the area of the shaded portion of the first rectangle.

<u><em>For the second one:</em></u>

The total area of both shaded and unshaded portions is equal to 6n(8n+14), which simplifies to 48n^2}+84n. The area of the middle white portion is 10n(4n+1), which simplifies to 40n^2+10n. To find the area of the shaded portion, we do 48n^2+84n-40n^2+10n. Combining like terms, we get 4n^2+94n as our expression for the area of the shaded portion of the second rectangle.

6 0
3 years ago
Read 2 more answers
Arc AD=98 and I need help with both problems below
Anni [7]

Answer:

arc DC = 64

angle DCQ = 32

Step-by-step explanation:

Hello There!

The circumference of a normal circle is 360

Given that arc AD = 98 and having found arc ABC we can find arc DC by subtract the known arcs from 360

360 - 98 - 198 = 64

Hence arc DC = 64

The problem wants us to find angle DCQ having found arc DC

Remember like stated before an included angle is equal to 1/2 its opposite arc

64/2=32

so angle DCQ = 32

5 0
3 years ago
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