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3 years ago

How do I do this I need help

Mathematics

1 answer:

wel3 years ago

4 0

The answer is -8=29 distribute the number to each side

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For an arithmetic sequence, a35=57. If the common difference is 5. Find a1 and the sum of the first 61 terms.

Flauer [41]

$\displaystyle\bf\\a_{35}=57\\r=5\\----\\a_1=?\\S_{61}=?\\----\\Solve:\\1)\\a_1=a_{35}-(35-1)\times r=57-34\times 5=57-170=-113\\\boxed{\bf a_1=-113}\\\\$

$\displaystyle\bf\\2)\\A_{61}=a_1+(61-1)\times r=-113+60\times5=-113+300=187\\\\S_{61}=(-113)+(-108)+(-103)+...+(-8)+(-3)+2+7+12+...+187\\\\S_{61}=SA+SB\\\\SA=(-113)+(-108)+(-103)+...+(-8)+(-3)=-(3+8+103+108+113)\\\\n=\frac{113-8}{5}+1=\frac{105}{5}+1=21+1=22~terms\\SA=-\Big( \frac{n(113+3)}{2} \Big)=-\Big( \frac{22\times116}{2} \Big)=-11\times116 =-1276$

$\displaystyle\bf\\SB=2+7+12+...+187\\\\n=\frac{187-2}{5}+1=\frac{185}{5}+1=37+1=38~terms\\\\SB=\frac{n(187+2)}{2}=\frac{38\times189}{2}=19\times189=3591\\\\S_{61}=SA+SB=-1276+3591=2315\\\\\boxed{\bf S_{61}=2315}$

8 0

3 years ago

I and m are parallel to each other

Misha Larkins [42]

And what I need more information to answer your question.

4 0

3 years ago

Read 2 more answers

Solve for x:

pentagon [3]

Answer:

2<x<3

Step-by-step explanation:

4x-4<8 AND 9x+5>23

Solve the first inequality

4x-4<8

Add 4 to each side

4x-4+4 <8+4

4x<12

Divide by 4

4x/4 <12/4

x <3

Solve the second inequality

9x+5>23

Subtract 5 from each side

9x+5-5>23-5

9x >18

Divide by 9

9x/9>18/9

x>2

Put together

x<3 and x>2

2<x<3

3 0

3 years ago

A survey of 46 college athletes found that 24 played volleyball, while 22 played basketball. a) If we pick one athlete survey pa

PSYCHO15rus [73]

Answer:

A) $\dfrac{11}{23}$

B) $\dfrac{88}{345}$

Step-by-step explanation:

A survey of 46 college athletes found that

24 played volleyball,
22 played basketball.

A) If we pick one athlete survey participant at random, the probability they play basketball is

$P_1=\dfrac{22}{46}=\dfrac{11}{23}$

B) If we pick 2 athletes at random (without replacement),

the probability we get one volleyball player is $\dfrac{24}{46}=\dfrac{12}{23};$
the probability we get another basketball player is $\dfrac{22}{45}$ (only 45 athletes left).

Thus, the probability we get one volleyball player and one basketball player is

$P_2=\dfrac{12}{23}\cdot \dfrac{22}{45}=\dfrac{88}{345}$

5 0

4 years ago

What is the area of a cirlcle that's 4cm

Elena-2011 [213]

If the radius of the circle is 4 than the area would be 50.27.

If you are saying that 4 is the diameter, than divide that by 2 to get the radius which is 2. The area for this would be 12.57.

I don’t know which one you mean but hope this helps :))

7 0

3 years ago