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nalin [4]
3 years ago
15

Factor 3x^2 - 2x - 1 ​

Mathematics
1 answer:
just olya [345]3 years ago
7 0

Answer:

(3x+1) (x-1)

Step-by-step explanation:

.................

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The product of 3 and m
Gala2k [10]
3(m)
Product = multiplication
4 0
4 years ago
What equation results from completing the square and then factoring x^2-12x=58
Anna11 [10]

Just add the numbers then subtract from 12

8 0
3 years ago
What is the explicit formula for the nth term of a(n)=12a(n-1, where the 1st term is .001?
masya89 [10]
\left\{\begin{array}{ccc}a_1=0.001\\a_n=12a_{n-1}\end{array}\right\\\\\boxed{a_n=0.001\cdot12^{n-1}}
7 0
3 years ago
For males in a certain town, the systolic blood pressure is normally distributed with a mean of 130 and a standard deviation of
valina [46]
Average systolic blood pressure = x = 130
Standard deviation = s = 6

We are to find interval that represents the systolic blood pressure of middle 99.7% of the males.

According to the empirical rule:
a) 68% values lie within 1 standard deviation of the mean
b) 95% values lie within 2 standard deviation of the mean
c) 99.7% values lie within 3 standard deviation of the mean

So, 99.7% value will lie within 3 standard deviations from the mean.

We can express this range as:
( x - 3s, x + 3s)
= (130 - 3(6), 130 +3(6))
= ( 130 - 18, 130 + 18)
= ( 112, 148 )

Thus the interval from 112 to 148 contains the systolic blood pressure of middle 99.7% of the males in the certain town
5 0
3 years ago
Sarafina and Katie have between $105 and $420 dollars to spend on jewelry for Christmas presents for their friends. If they buy
algol13

Answer:

66

Step-by-step explanation:

105+420=525   (Total Money)

7x3.25=22.75   (Cost of all bracelets)

8x11.74=93.92   (Cost of all necklaces)

93.92+22.75=116.67   (Cost of all Christmas presents)

525-116.67=408.33   (Total money - Cost of all Christmas presents)

408.33/6.15=66.39...   (Amount of necklaces)

since in real life you can only buy a whole number of things, you would round down 66.39 to 66. I hope this helped!

5 0
3 years ago
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