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3 years ago

Find two decimals with a product between 1 and 2

1 answer:

4 0

Here is a method that makes it seem easier.
Write down any number between 51 and 59. 
For example you might choose 57 = 3*19 
Divide both numbers by 10 and write the answer as 
0.3 * 1.9 = 0.57

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Can you solve it ????

Dima020 [189]

Angle ABD=87 degrees
angle ABC+angle CBD= angle ABD
Therefore, 9x-1+6x+58=87
15x+57=87
15x=87-57
15x=30
x=30/15
x=2

Angle ABC= 9x-1
=9(2)-1
=18-1
=17 degrees

7 0

3 years ago

(50 Points & Brainliest)

givi [52]

Answer:

Answer: There is no relationship between hours spent cycling and hours spent playing football. I did flvs and I got this question correct.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the value of 100?

Nesterboy [21]

Answer:

Step-by-step explanation:

Means back the numbers into multiples of several small numbers

Like:; 1. We take LCM of 40

Just break into multiples of small number

40= 2×2×2×5

2. We take LCM of 50

50= 5×5×2

So LCM for 100 is 2×2×5×5

after that see the pairs in the LCM like 2×2 or 3×3 or 4×4(same numbers)

Then write the the single number in place of two multipled numbers

Like:; 2×2 is written as 2 // 3×3 is written as 3

So we can write 100 into 2×2×5×5 and then after selecting pairs (2×2)×(5×5)

write pairs in single number 2×5

And so we get 2×5=10

So we find root of 100 that is 10

8 0

3 years ago

Read 2 more answers

A random sample of 50 students from a high school with 900 students is surveyed. Each student is asked what science class he or

strojnjashka [21]

Answer: 50 and 900 is correct

Step-by-step explanation:

50 and or 100

4 0

2 years ago

Let z denote a random variable that has a standard normal distribution. Determine each of the probabilities below. (Round all an

Gelneren [198K]

Answer:

(a) P (Z < 2.36) = 0.9909 (b) P (Z > 2.36) = 0.0091

(e) P (-0.77< Z > -0.55) = 0.0705 (f) P (Z > 3) = 0.0014

(g) P (Z > -3.28) = 0.9995 (h) P (Z < 4.98) = 0.9999.

Step-by-step explanation:

Let us consider a random variable, $X \sim N (\mu, \sigma^{2})$ , then $Z=\frac{X-\mu}{\sigma}$ , is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, $Z \sim N (0, 1)$ .

In statistics, a standardized score is the number of standard deviations an observation or data point is above the mean. The z-scores are standardized scores.

The distribution of these z-scores is known as the standard normal distribution.

(a)

Compute the value of P (Z < 2.36) as follows:

P (Z < 2.36) = 0.99086

≈ 0.9909

Thus, the value of P (Z < 2.36) is 0.9909.

(b)

Compute the value of P (Z > 2.36) as follows:

P (Z > 2.36) = 1 - P (Z < 2.36)

= 1 - 0.99086

= 0.00914

≈ 0.0091

Thus, the value of P (Z > 2.36) is 0.0091.

(c)

Compute the value of P (Z < -1.22) as follows:

P (Z < -1.22) = 0.11123

≈ 0.1112

Thus, the value of P (Z < -1.22) is 0.1112.

(d)

Compute the value of P (1.13 < Z > 3.35) as follows:

P (1.13 < Z > 3.35) = P (Z < 3.35) - P (Z < 1.13)

= 0.99960 - 0.87076

= 0.12884

≈ 0.1288

Thus, the value of P (1.13 < Z > 3.35) is 0.1288.

(e)

Compute the value of P (-0.77< Z > -0.55) as follows:

P (-0.77< Z > -0.55) = P (Z < -0.55) - P (Z < -0.77)

= 0.29116 - 0.22065

= 0.07051

≈ 0.0705

Thus, the value of P (-0.77< Z > -0.55) is 0.0705.

(f)

Compute the value of P (Z > 3) as follows:

P (Z > 3) = 1 - P (Z < 3)

= 1 - 0.99865

= 0.00135

≈ 0.0014

Thus, the value of P (Z > 3) is 0.0014.

(g)

Compute the value of P (Z > -3.28) as follows:

P (Z > -3.28) = P (Z < 3.28)

= 0.99948

≈ 0.9995

Thus, the value of P (Z > -3.28) is 0.9995.

(h)

Compute the value of P (Z < 4.98) as follows:

P (Z < 4.98) = 0.99999

≈ 0.9999

Thus, the value of P (Z < 4.98) is 0.9999.

**Use the z-table for the probabilities.

3 0

3 years ago