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Grace [21]
3 years ago
6

there are 4 performers who will present their comedy acts this weekend at a comedy club. how many different ways are there to sc

hedule their appearances
Mathematics
1 answer:
DiKsa [7]3 years ago
8 0
There should be 6 per number
ex.
1234
1243
1342
1324
1432
1423
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And it's elimination using addition and subtraction <br> x-y=1<br> x+y=3
MatroZZZ [7]
Get one x+y=3 to y=x+3 and plug it into x-y=1 and you get x-(x+3)=1. Destitute the x and solve. Once you get what x equals plug it to to either equation for the value of x and solve for y
7 0
4 years ago
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70 POINTS PLEASE HELP!! Use the two equations: f (x) =x^2 and g (x) =4x+1 to determine the solutions to the following function o
bagirrra123 [75]
<h2><em><u>My</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em></h2>

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<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>#brainliestbunch</em><em> </em><em>=</em><em>)</em><em> </em>

6 0
3 years ago
Twenty seven less than eight times a number is equal to five. What is the number?
Korvikt [17]
<h3><u>The unknown number is equal to 4.</u></h3>

8x - 27 = 5

Add 27 to both sides.

8x = 32

Divide both sides by 8

x = 4

6 0
3 years ago
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If p(a|b) = 0.35, p(b) = 0.75 and p(a) = 0.44 are the events a and b independent ?
MatroZZZ [7]
Hello : 
note 1 : 
 p(A|B) = p(A∩B)/<span> p(B)

note 2 : 
</span> A and B independent: p(A∩B) = p(A)×p(B)
calculate : p(A∩B)
p(A∩B) = p(A|B)×p(B)
p(A∩B) = 0.35 ×0.75 = 0.2625
but :  p(A)×p(B) = 0.44×0.75 = 0.33
 conclusion : 
<span>the events A and B  are not  independent ?</span>
6 0
3 years ago
How do i solve 2x=-3<br>i need answer ASAP​
Mrrafil [7]

Answer:

x = \frac{-3}{2} \\or \\x = -\frac{3}{2}\\or\\-1.5

Step-by-step explanation:

2x = -3

divide 2 from both sides

x = \frac{-3}{2} \\\\or \\x = -\frac{3}{2}

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3 years ago
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