Answer:
![\large\boxed{4\sqrt[3]{64}=16}](https://tex.z-dn.net/?f=%5Clarge%5Cboxed%7B4%5Csqrt%5B3%5D%7B64%7D%3D16%7D)
Step-by-step explanation:
![\sqrt[3]{a}=b\iff b^3=a\\\\4\sqrt[3]{64}=(4)(4)=16\\\\\sqrt[3]{64}=4\ \text{because}\ 4^3=64](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Db%5Ciff%20b%5E3%3Da%5C%5C%5C%5C4%5Csqrt%5B3%5D%7B64%7D%3D%284%29%284%29%3D16%5C%5C%5C%5C%5Csqrt%5B3%5D%7B64%7D%3D4%5C%20%5Ctext%7Bbecause%7D%5C%204%5E3%3D64)
<h2>Correct question;</h2>
<h2>

</h2><h2>Required solution;</h2>
<h3>↠ Multiply the terms with the same base by adding their exponents</h3>
<h2>

</h2><h3>↠ Add the numbers</h3>
<h2>

</h2>
After expanding the answer will be 81

Hope it helps...
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J, all the other answer are constant to 5 and 3. 5 and 3 do not have multiples to both equal J.
The r-value, or common ratio, can be calculated by dividing any two consecutive terms in a geometric sequence.