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Lana71 [14]
2 years ago
9

The number of tourists visiting a city doubles every month during the two-month period beginning in Jan. 1st and ending in Feb.

28th each year. If the number of tourists who visited the city in the beginning of January in that particular year was x, how many tourists visited the city at the end of February that
Mathematics
1 answer:
ohaa [14]2 years ago
6 0

Answer:

2x

Step-by-step explanation:

The number of tourists visiting at January is given as x and since the number of tourists doubles every month then by the end of feburary will be 2 multiplied by x

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What is the product of 4 and 8V200 in simplest radical form?
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2 years ago
Is it <br> a.x = _<br> b. the solution is all real numbers <br> c. there is no solution
Zielflug [23.3K]

The solution to the given algebraic equation 1000(7x - 10) = 50(292 + 100x) is; x = 12.3

<h3>How to simplify algebraic equations?</h3>

We want to simplify the algebraic equation;

1000(7x - 10) = 50(292 + 100x)

The first step is to use distributive property of equality to expand the bracket to get;

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Use division property of equality to divide both sides by 2000 to get;

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x = 12.3

Thus, we can conclude that the solution to the given algebraic equation 1000(7x - 10) = 50(292 + 100x) is; x = 12.3

Read more about algebraic equations at; brainly.com/question/723406

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7 0
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