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OLga [1]
3 years ago
15

Explain why you write a mixed number as a fraction before using it as a dividend or divisor.

Mathematics
1 answer:
Eduardwww [97]3 years ago
3 0

Answer:

I think it's because it is easier to solve when put into equations.

Step-by-step explanation:

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What is the midpoint of AB
Julli [10]

Answer:

What you have is correct. Great job!

Step-by-step explanation:

3 0
3 years ago
Solve x – 2y = 6 3x – 6y = 18
VashaNatasha [74]
X will equal 0 and y will equal -3
6 0
3 years ago
Pls help!
sergejj [24]

To fill in the values we have the following

a. log6⁰, log 2 . 1, log 8/3

b. log 1 .4 , 1 , log 4. 6

c. log 9/2, log 3. 5 , log 5⁷

<h3>How to find the logarithm of a number</h3>

To do this, you have to decide on that particular number that you want to find the logarithm on. Next you have to find the base of that number.

The logarithm of the number is the power that it would have to be raised for us to obtain a different number. You have to note that the logarithm of the number is the exponent that a base would have to be raised up to in order to get a particular number.

Log6⁰ for instance would give us the solution of 1 as the answer. While telling us that we have that the exponent is 0 while the base is 6.

One good property of logarithm is that log m/n = log m - log n also when we have log mn, it is the same as log m * log n

Read more on the logarithm of a number here: brainly.com/question/1807994

#SPJ1

5 0
2 years ago
Which matrix equation represents the system of equations?<br><br> {-x+ 2y = 0 <br> y= -2
Snowcat [4.5K]

We are given a system of equations,

\begin{cases}-x+2y=0\\y=-2\\ \end{cases}

This will translate into a 2x2 matrix of coefficients (because 2 equations and 2 unknowns),

\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}

The matrix will then be applied to the vector (lower dimensions on top),

\begin{bmatrix}x\\y\\ \end{bmatrix}

And the result vector will be whats on the other side of equals sign,

\begin{bmatrix}0\\-2\\ \end{bmatrix}

So to put everything together,

\begin{bmatrix}-1&2\\0&1\\ \end{bmatrix}\begin{bmatrix}x\\y\\ \end{bmatrix}=\begin{bmatrix}0\\-2\\ \end{bmatrix}

Hope this helps :)

6 0
3 years ago
69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69+69
Alik [6]

Answer:

6624 is the answer

If this answer helps you plz mark as brainlist

5 0
3 years ago
Read 2 more answers
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