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Dima020 [189]
3 years ago
9

Which of the following is an example of Interspecific competition?

Biology
2 answers:
DENIUS [597]3 years ago
4 0

one! i wish you good luck on your test/assignment <3

bazaltina [42]3 years ago
4 0
The first one should be correct
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Cellular respiration and fermentation both. . A. begin with the breakdown of glucose in glycolysis. . B.produce the same number
Rus_ich [418]

The correct answer is:

A. begin with the breakdown of glucose in glycolysis.

Explanation:

They both begin with a sequence of reactions known as glycolysis, which breaks glucose particles into smaller pyruvate molecules. They are also related in that through both processes, ATP is generated for the cell to use. Glycolysis is the metabolic pathway that transforms glucose C6H12O6, into pyruvate, CH3COCOO− + H+. The free energy delivered in this process is applied to form the high-energy molecules ATP and NADH .

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3 years ago
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All atoms of the same element must have the same number of
kherson [118]

Answer:

protons..................

4 0
3 years ago
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The "supplement facts" panel on dietary supplements resembles the ________________ ________________ and is required on all dieta
olasank [31]

The supplementary fact panel is used for the dietary supplements. This supplement fact panel on the dietary supplements is similar to the nutritional fact panel, which is present on most of the packaged products. The supplementary fact panel denotes the information about the beverage and the benefits of the product are listed under it too.

Hence, the answer is 'nutritional facts on foods'.

4 0
3 years ago
A pure-breeding, tall pea plant with white flowers is crossed with a pure-breeding, short plant with red flowers. The F1 plants
DIA [1.3K]

Answer:

Null Hypothesis -

The observed frequency is approximately equal to the expected frequency of phenotype.

Explanation:

Pure Breeding Cross - TTww x ttWW

Genotype of offspring in F2 generation - TtWw

Null Hypothesis -

The observed frequency is approximately equal to the expected frequency of phenotype.

The chi square analysis is attached

The degree of freedom for this question is 3

The p value for X^2 estimated through chi square test is 0.5

Hence the null hypothesis is accepted.

6 0
3 years ago
A group of scientists designed a clinical study to investigate the effects of cholesterol deficiency in humans. For the duration
viva [34]

Answer:

c. none of the subjects to show signs and symptoms of a cholesterol deficiency during the entire study.

Explanation:

this is because the blood cholesterol is from two sources. Nearly 80% of the cholesterol the body needs  are made by the liver and intestine.certain small amounts are also produced in the adrenal glands and the reproductive organs.The remaining fragment amounts comes from the diets.

Therefore even if these subjects  were fed with diet without cholesterol, it will not have any significant effects on the body cholesterol composition. Therefore no symptoms of its deficiency will be observed.

Generally it biosynthesis is regulated by the amount of cholesterol present in the blood.

3 0
3 years ago
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