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yarga [219]
3 years ago
12

A thermometer reads -111.1 °F. What is the temperature in °C?

Chemistry
1 answer:
brilliants [131]3 years ago
5 0
The temperature is -79.5
To find C, the formula is
K-273.15=C
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Calculate the number of oxygen atoms in 2.00 moles of Mn2O7
cluponka [151]
First you should know that there is seven oxygen atoms in one Mn2O7
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Then you multiply this no. with Avagadro no....
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7 0
3 years ago
How many equivalents are present in 13.5g of Al3+
gogolik [260]
Answer:

= 1.5 eq

Explanation:

One definition of an equivalent weight is that it is mass of a substance that gains or loses 1 mole of electrons.
Al3+ has lost 3 e-, so there are 3 equivalent weights in 1 mol Al3+.

1 mol Al3+ =3 eq. wts.
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4 0
3 years ago
If a pea plant is tall, and tallness in pea plants is dominant over shortness, what is the phenotype of the pea plant?
Firlakuza [10]

Answer:

The height of the plant is controlled by two alleles - the dominant 'T' for tallness and recessive 't' for shortness of the plant. The dominant allele represses the expression of the recessive allele. The recessive allele is expressed only in the homozygous state (tt)

6 0
3 years ago
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The reaction below was carried out in an acidic solution. upper i minus, plus upper i upper o minus subscript 3 right arrow uppe
maria [59]

The reaction is an unbalanced redox reaction hence, the reaction  can be balanced by using the half-reaction method.

<h3>What is a redox reaction?</h3>

The term redox reaction refers to the reactionnin which electrons are transferred hence one specie is oxidized while the other specie is reduced.

Looking at the reation as shown, we can see that the reaction is an unbalanced redox reaction hence, the reaction  can be balanced by using the half-reaction method.

Learn more about redox reaction: brainly.com/question/13293425

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6 0
2 years ago
A 0.04358 g sample of gas occupies 10.0-ml at 292.0 k and 1.10 atm. upon further analysis, the compound is found to be 25.305% c
kirill [66]
<span>Answer: A 0.04403 g sample of gas occupies 10.0-mL at 289.0 K and 1.10 atm. Upon further analysis, the compound is found to be 25.305% C and 74.695% Cl. What is the molecular formula of the compound? --------------------------------------... Seems like I did a problem very similar to this--this must be the "B" test. But the halogen was different. 25.305% C/12 = 2.108 74.695% Cl/35.5 = 2.104 So the empirical formula would be CH. However, there are many compounds which fit this bill, so we have to use the gas data. (And I made, in the previous problem, the simplifying assumption that 289C and 1.10 atm would offset each other, so I'll do that, too.) 0.044 grams/10 ml = x/22.4 liters 0.044g/0.010 liters = x/22.4 liters 22.4 liters/0.010 liters = 2240 (ratio) 2240 x .044 = 98.56 (actual atomic weight) CCl = 35.5+12 or 47.5, so two of those is 95 grams/mole. This is sufficiient to distinguish C2CL2, (dichloroacetylene) from C6CL6 (hexachlorobenzene) which would mass 3 times as much.</span>
3 0
3 years ago
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