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LiRa [457]
3 years ago
14

The __________________ of a solution tells how many moles of solute are present per liter.

Chemistry
2 answers:
Stels [109]3 years ago
5 0

Answer:

The MOLARITY of a solution tells how many moles of solute are present per liter

Explanation:

Molarity is a sort of concentration.

It is written as M (mol/L)

Soloha48 [4]3 years ago
3 0

Answer: molarity

Explanation: molarity is expressed as number of moles of a solute in one litre of a solution, that is mol/litre. Molarity is the unit of concentration.

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Which of these structures is found in all types of plant and animal cells
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Answer:

Hi, There!

which of these structures is found in all types of plant and animal cells

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5 0
3 years ago
8. What is the name of this compound?
olga2289 [7]

Answer:

tert-butyl bromide

Explanation:

sec-butyl bromide

CH3 -CH-CH2-CH3

         Br

tert-butyl bromide

       CH3

CH3-C- Br

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isobutyl bromide

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4 years ago
What is albert einstein's nationality?
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German,Prussian,Weimar,American,Swiss
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What would be the composition and ph of an ideal buffer prepared from lactic acid (ch3chohco2h), where the hydrogen atom highlig
Mashutka [201]

Answer:

P_H =2.86

c=1.4\times 10^{-4}

Explanation:

first write the equilibrium equaion ,

C_3H_6O_3  ⇄ C_3H_5O_3^{-}  +H^{+}

assuming degree of dissociation \alpha =1/10;

and initial concentraion of C_3H_6O_3 =c;

At equlibrium ;

concentration of C_3H_6O_3 = c-c\alpha

[C_3H_5O_3^{-}  ]= c\alpha

[H^{+}] = c\alpha

K_a = \frac{c\alpha \times c\alpha}{c-c\alpha}

\alpha is very small so 1-\alpha can be neglected

and equation is;

K_a = {c\alpha \times \alpha}

[H^{+}] = c\alpha = \frac{K_a}{\alpha}

P_H =- log[H^{+} ]

P_H =-logK_a + log\alpha

K_a =1.38\times10^{-4}

\alpha = \frac{1}{10}

P_H= 3.86-1

P_H =2.86

composiion ;

c=\frac{1}{\alpha} \times [H^{+}]

[H^{+}] =antilog(-P_H)

[H^{+} ] =0.0014

c=0.0014\times \frac{1}{10}

c=1.4\times 10^{-4}

6 0
4 years ago
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