Here's a way to do it.
Let 4e +2 = 5n +1 . . . . . . for some integer n
Then e = (5n -1)/4 = n + (n -1)/4
We want (n-1)/4 to be an integer, so let it be integer m.
... m = (n -1)/4
... 4m = n -1
... 4m +1 = n
Substituting this into our expression for e gives
... e = (5(4m+1) -1)/4 = (20m +4)/4 = 5m +1
e = 5m+1 for any integer m
Answer:
48
Step-by-step explanation:
minus 6 every number
Just wondering, Is there options?
<span>I think you know by now that I strongly encourage everyone to shoot a proper round and whatever the score is, to submit it to our Records Officer, Giles Conn. Think of it as an annual competition (a) to wear him out, and (b) to see if we can altogether, beat last year's tally. Also, for the outdoor season rounds, you can have a go at achieving the St Wilfred trophy. I've won it 3 years running (last year jointly with Terry Skinner), but they wouldn't let me keep it this time, sadly.</span>
Answer:
A=158
Step-by-step explanation: SA = 2 × l × w + 2 × l × h + 2 × w × h
