All categories

3 years ago

What is 3Vsquare27 + v64square -2

Mathematics

1 answer:

serg [7]3 years ago

8 0

Answer:

Step-by-step explanation:

I think you are inventing symbols, which turns your question into a guessing game. You are better off describing the math symbols in words. Or post a picture.

I’m guessing that the math expression is ∛27 + √64² - 2 = 3 + 64 - 2 = 65

You might be interested in

What percent of 120 is 7.8?

lora16 [44]

Answer:

6.5%

Step-by-step explanation:

Is means equals and of means multiply

Let P be the percent

P * 120 = 7.8

Divide each side by 120

P* 120/120 = 7.8/120

P = .065

Change to percent form

6.5%

3 0

3 years ago

A city with a population of 700,000 has been growing at a rate of 2% per year. If this rate continues, what would the population

Mars2501 [29]

Answer:

450,900

Step-by-step explanation:

3 0

2 years ago

Jean jogs 2/3 km at 12 km and then walks 1 1/3 km at 8km/h.Find her average for the whole journey.

telo118 [61]

Answer:80mi/hr * 3.5hrs

5 0

3 years ago

Find the corresponding effective interest rate for 3% per year compounded continuously?

jeyben [28]

Answer:

3.045%.

Step-by-step explanation:

We are asked to find the corresponding effective interest rate for 3% per year compounded continuously.

We will use effective interest formula to solve our given problem.

$r=e^i-1$ , where,

r = Effective interest rate,

e = Mathematical constant,

r = Interest rate in decimal form.

Let us convert given interest rate in decimal form.

$3\%=\frac{3}{100}=0.03$

Substitute values:

$r=e^{0.03}-1$

$r=1.030454533953517-1$

$r=0.030454533953517$

$r\approx 0.03045$

Convert into percentage:

$0.03045\times 100\%=3.045\%$

Therefore, the corresponding interest rate would be 3.045%.

3 0

3 years ago

Eliminate the parameter. x = t^2 + 1, y = t^2 - 1.

Maksim231197 [3]

Answer:

Eliminating the parameter, the equation is $y = x - 2$

Step-by-step explanation:

We are given the following parametric equations:

$x = t^2 + 1$

$y = t^2 - 1$

We want to eliminate the parameter t. From the first equation:

$x = t^2 + 1$

$t^2 = x - 1$

Replacing in the second equation:

$y = x - 1 - 1$

$y = x - 2$

Eliminating the parameter, the equation is $y = x - 2$

7 0

3 years ago