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Hatshy [7]
3 years ago
9

Find the slope containing the points (5, 2) and (1, 6)

Mathematics
1 answer:
djverab [1.8K]3 years ago
4 0
-1. Remember rise over run

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9. The radius of a circle is 6.
Arlecino [84]

Answer:

12,5.196

Step-by-step explanation:

given that the radius of a circle is 6.

We have any tangent drawn from outside point there will be two tangents of equal length and also the line joining point of intersection of tangent with centre of circle will bisect the angle between the tangents.

When angle between the two tangents is 60, we have the right triangle formed by radius, one tangent, and line joining point of intersection of tangent with centre of circle with angles 30,60 and 90

Hence the hypotenuse = length of line segment of tangent = 2 (radius) = 12

Part 2:

When angle between tangents is 120, we have 60,30,90 right triangle and hence length of tangent = radius * sin 60

= 6*\frac{\sqrt{3} }{2} \\=5.196

7 0
3 years ago
Simplify the sum: (5u^3+7u^2+7)+(7u^3-6u+5)
viktelen [127]
I hope you understand it

5 0
4 years ago
The options are<br> 1/4<br> 1/5<br> 1/6<br> 1/12
trapecia [35]
1/5 because 60 (the sum) divided by 12 is 5
8 0
3 years ago
Create a factorable polynomial with a GCF of 7. Rewrite that polynomial in two other equivalent forms. Explain how each form was
Aleks [24]
This looks like an odd problem.
Just start with a simple expression with 7 as a factor, and then multiply it out.
For example:
7(x+1)(x+2)
Here 7 could be the GCF.
Now multiply it out:
7(x^2+3x+2) =
7x^2+21x+14
So our factorable polynomial is 7x^2+21x+14
And its two equivalent forms are: 
7(x^2+3x+2)and7(x+1)(x+2)

7 0
3 years ago
Y=15 + x what is the ordered pair?
valina [46]

Answer: (0,15) (1,16) (2,17)

Step-by-step explanation:

4 0
3 years ago
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