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3 years ago

Idris bought 9 tomato plants for $33.12. How much did each tomato plant cost?

Mathematics

2 answers:

Marysya12 [62]3 years ago

7 0

Answer:

9 tomat plant cost= 33.12

each tomato plant cost = 33.12 / 9

answer = 3.68 dalours

melisa1 [442]3 years ago

3 0

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The regular price of an item at a store is p dollars. The item is on sale for 20% off the regular price. Some of the expressions

ruslelena [56]

Answer:

Expression B: 0.8p

Expression D: p - 0.2p

Step-by-step explanation:

The regular price of an item at a store is p dollars. The item is on sale for 20% off the regular price. Some of the expressions shown below represent the sale price, in dollars, of the item.

Expression A: 0.2p

Expression B: 0.8p

Expression C:1 - 0.2p

Expression D: p - 0.2p

Expression E: p - 0.8p

Which two expressions each represent the sale price of the item?

Regular price of the item = $p

Sale price = 20% off regular price

Sale price = $p - 20% of p

= p - 20/100 * p

= p - 0.2 * p

= p - 0.2p

= p(1 - 0.2)

= p(0.8)

= 0.8p

The sale price is represented by the following expressions

Expression B: 0.8p

Expression D: p - 0.2p

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3 years ago

What is the area of this triangle?

Ganezh [65]

Answer:

$\boxed{\bold{120 \ Units^2}}$

Step By Step Explanation:

Area Of Triangle: $\bold{\frac{1}{2}Base \ \cdot \ Height}$

Base: 10

Height: 24 (This triangle has a right angle, so we use the height based off of the 90° angle, which is 24)

Insert Numbers Into Equation

$\bold{\frac{1}{2}10 \ \cdot \ 24}$

$\bold{\frac{1}{2}}$ 10 = 5

$\bold{5 \ \cdot \ 24 \ = \ 120}$

➤ $\boxed{\bold{Mordancy}}$

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4 years ago

Differentiating a Logarithmic Function in Exercise, find the derivative of the function. See Examples 1, 2, 3, and 4.

wlad13 [49]

Answer:

$\frac{dy}{dx}=\frac{x(1-2lnx)}{x^{4}}$

Step-by-step explanation:

To solve the question we refresh our knowledge of the quotient rule.

For a function f(x) express as a ratio of another functions u(x) and v(x) i.e

$f(x)=\frac{u(x)}{v(x)}\\$ , the derivative is express as

$\frac{df(x)}{dx}=\frac{v(x)\frac{du(x)}{dx}-u(x)\frac{dv(x)}{dx}}{v(x)^{2} }$

from $y=lnx/x^{2}$

we assign u(x)=lnx and v(x)=x^2

and the derivatives

$\frac{du(x)}{dx}=\frac{1}{x}\\\frac{dv(x)}{dx}=2x\\$ .

Note the expression used in determining the derivative of the logarithm function.it was obtain from the general expression of logarithm derivative i.e $y=lnx\\\frac{dy}{dx}=\frac{1}{x}$