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3 years ago

Afla suma dintre probusul si catul numerelor 10 si 5

Mathematics

1 answer:

ELEN [110]3 years ago

7 0

Answer:

The answer is 1

Step-by-step explanation:

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If you multiply me by 2, then divide the answer by 2, then divide again by 2, you get a quotient of 5. What number am I?

Anuta_ua [19.1K]

The number is 10
10*2=20
20/2=10
10/2=5

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3 years ago

What is the multiplicative inverse of 1 over 2

SpyIntel [72]

Answer:

explanation;

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4 years ago

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HELP FAST 25. What is the value of x in the solution to this system of equations?

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3 years ago

(Hypothetical.) Suppose five measurements of the volume of a liquid yield the following data (in milliliters).

Digiron [165]

Answer:

The 95% confidence interval for the measurements is [48.106, 53.494].

Step-by-step explanation:

The average M of this sample is

$M=\dfrac{1}{5}\sum_{i=1}^5x_i=\dfrac{1}{5}(52+48+49+52+53)\\\\\\M=\dfrac{254}{5}=50.800$

The standard deviation s of this sample is

$s=\sqrt{\dfrac{1}{(n-1)}\sum_{i=1}^5(x_i-M)^2}$

$s=\sqrt{\dfrac{1}{4}\cdot [(52-50.8)^2+(48-50.8)^2+(49-50.8)^2+(52-50.8)^2+(53-50.8)^2]}$

$s=\sqrt{\dfrac{1}{4}\cdot [(1.44)+(7.84)+(3.24)+(1.44)+(4.84)]}=\sqrt{\dfrac{18.8}{4}}=\sqrt{4.7}\\\\\\s=2.168$

The degrees of freedom are

$df=n-1=5-1=4$

Then, the critical value of t for a 95% CI and 4 degrees of freedom is t=2.776.

The margin of error of the CI is:

$E=t\cdot s/\sqrt{n}=2.776\cdot 2.17/\sqrt{5}=6.024/2.236=2.694$

Then, the lower and upper bounds of the CI are:

$LL=50.800-2.694=48.106\\\\UL=50.800+2.694=53.494$

The 95% confidence interval for the measurements is [48.106, 53.494].

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4 years ago

a recent study showed that the average high school basketball team score 76 points a game with a standard deviation of 8.4 point

krok68 [10]

Answer: 0.0766

Step-by-step explanation:

Let x be the random team scores.

Given: Mean = 76

Standard deviation = 8.4

We assume that x follows normal distribution.

The probability that a random team scores less than 64 points = P(x<60)

$=P(\frac{x-\mu}{\sigma}$

Hence, the probability that a random team scores less than 64 points =0.0766

3 0

3 years ago