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3 years ago

I don't know how to do this

Mathematics

1 answer:

aliina [53]3 years ago

7 0

Is that division or square root?

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The range of F(x) = 5.2% is all positive real numbers. O A. True O B. False

kirza4 [7]

Answer:

If im not mistaken its true

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4 years ago

How do we name a minor arc?

erastova [34]

A minor arc (left figure) is an arc of a circle having measure less than or equal to ( radians). SEE ALSO: Arc, Major Arc, Semicircle.

7 0

3 years ago

Can someone help me please ill give brainy

finlep [7]

Answer:

the equation of this line is x = -5

Step-by-step explanation:

8 0

3 years ago

What is the answer to this question?

enot [183]

Answer:

X = 20.5

the equation

x+5*x-2=44

combine like terms

2x+3=44

and so on....

3-44=41

41/2 = 20.5

Now x=20.5

3 0

3 years ago

Read 2 more answers

Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

The question is

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

5 0

3 years ago