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sveta [45]
3 years ago
6

I need help please help

Mathematics
1 answer:
goblinko [34]3 years ago
4 0

Answer:

224 m^2

Step-by-step explanation:

Assuming the 2 triangles are the same area.

The area of a triangle is (1/2)bh, and since there are 2 triangles we can write it like this: 2((1/2)bh) = bh

Now, we can substitute the values: 12 x 8 = 96

For the rectangles, 2 of the rectangles have area of 10 x 4 = 40. So, 80 since there are 2. Then the middle rectangle has length 12, so 12 x 4 = 48.

We can add the values together now to get 96 + 80 + 48 = 224

So, 224 m^2.

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Will paid $2.73 for 3.5 pounds of bananas. What was the cost per pound of the bananas?
Alex73 [517]

Answer:

0.78¢

Step-by-step explanation:

if 3.5 lbs of bananas is $2.73, then we need to divide each side by 3.5 to get 1 lb of bananas

1 lb = 0.78¢

To check our work, we can do 0.78x3.5 = 2.73

Hope this helps! Please mark Brainliest if this helped :)

5 0
3 years ago
Harley had $250.00 in her savings account in january. In july, she had $425.00. what is the percentage of increase in her saving
zlopas [31]

Answer:

d

Step-by-step explanation:

425-250=175

175/250=0.7

70%

3 0
3 years ago
Evaluate -x+4 when x = -2
musickatia [10]

Answer:

<h2>6</h2>

Step-by-step explanation:

f(x)=-x+4

f(-2)=-(-2)+4

f(-2)=+2+4

f(-2)=6

8 0
3 years ago
Read 2 more answers
En una sala de teatro havian 7 filas 23 sillas cada una acaban de quitar 8 de las sillas ¿cuantas sillas quedan?
LenaWriter [7]

Answer:

Quedan 153 sillas

Step-by-step explanation:

Primero sabemos que en una sala de teatro tenían 7 filas, y en cada una de esas filas habían 23 sillas.

Entonces, originalmente, el número total de sillas es 7 veces 23:

S = 7*23 = 161

Luego sabemos que quitan 8 de esas sillas, entonces el número de sillas que quedan es la diferencia entre el número original de sillas, 161, y 8, que nos da:

S = 161 - 8 = 153

Quedan 153 sillas

6 0
3 years ago
Find the sum of the first four terms of the geometric sequence shown below. 4​, 4/ 3​, 4/9​, ...
user100 [1]
It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is

S_4=4+\dfrac43+\dfrac49+\dfrac4{27}

It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.

Multiply the sum by 1/3 and you have

\dfrac13S_4=\dfrac43+\dfrac49+\dfrac4{27}+\dfrac4{81}

Now subtracting this from S_4 gives

S_4-\dfrac13S_4=4-\dfrac4{81}

That is, all the matching terms will cancel. Now solving for S_4, you
have

\dfrac23S_4=4\left(1-\dfrac1{81}\right)
S_4=6\left(1-\dfrac1{81}\right)
S_4=\dfrac{480}{81}=\dfrac{160}{27}
3 0
4 years ago
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