Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
Answer:
45/1 and 180/41. True
2. False
3. False
Step-by-step explanation:
Answer:
115
Step-by-step explanation:
4*2+8(2) = 24
31
7(2)+30 = 44
3*2-5(2)+20 = 6-10+20 = -4+20 = 16
24+31+44+16
115
Answer:
-1
onyl becausse they are basically -3 4 {r84 if u havent got to that yet basically no
Step-by-step explanation:
-3
