find the permimter of the quadrilateral if x=2 the perimiter is in inches the perimiters are (4x2+8x) (31 ) (7x+30) (3x2-5x+20)
2 answers:
Answer:
115
Step-by-step explanation:
4*2+8(2) = 24
31
7(2)+30 = 44
3*2-5(2)+20 = 6-10+20 = -4+20 = 16
24+31+44+16
115
7(2) + 30 = 14+30 = 44
3(2^2) -5(2)+20 = 12 - 10 + 20 = 22
4(2^2) +8(2) = 16 + 16 = 32
P = 31 + 44 + 22 + 32 = 129
The perimeter is 129 inches
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