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4 years ago

Anyone I need help at this dont type other things. Pls now I need the solution anyone.

Mathematics

1 answer:

abruzzese [7]4 years ago

6 0

Answer:

see explanation

Step-by-step explanation:

(a)

Since there are 360° in the complete pie chart the 40° represents

360° ÷ 40° = 9 parts of the chart

Since 40° represents 7 cars then there are a total of

9 × 7 = 63 cars in the car park

(b)

The circumference (C) of a circle is calculated as

C = πd ( d is the diameter )

Given C = 28 , then

πd = 28 ( divide both sides by π )

d = $\frac{28}{\pi }$

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Given the graph of a line y=−x. Write an equation of a line which is perpendicular and goes through the point (8,2).

coldgirl [10]

Answer:

y = x - 6

Step-by-step explanation:

The slope of y = -x is -1, so the slope of any line perpendicular to y = -x is +1. Thus,

y = mx + b becomes 2 = 1(8) + b, so that b = -6.

The desired equation is y = x - 6.

Check: Does (8,2) lie on this line? Is 2 = 8 - 6 true? YES.

6 0

4 years ago

Read 2 more answers

If a simple harmonic motion is described by x = 3 cos(πt), starting from t = 0 s, what is the first occurrence of a value of t f

poizon [28]

Answer:

The first occurence of t for which x = 0 is t = 0.5.

Step-by-step explanation:

The harmonic motion is described by the following equation.

$x(t) = 3\cos{\pi t}$

What is the first occurrence of a value of t for which x = 0?

This is t when $x(t) = 0$ . So

$x(t) = 3\cos{\pi t}$

$3\cos{\pi t} = 0$

$\cos{\pi t} = \frac{0}{3}$

$\cos{\pi t} = 0$

The inverse of the cosine is the arcosine. So we apply the arcosine function to both sides of the equality.

$\arccos{\cos{\pi t}} = \arccos{0}$

$\pi t = \frac{\pi}{2}$

$t = \frac{\pi}{2 \pi}$

$t = \frac{1}{2}$

$t = 0.5$

The first occurence of t for which x = 0 is t = 0.5.

3 0

3 years ago

Which of the following shows the extraneous solution to the logarithmic equation below? log Subscript 3 Baseline (18 x cubed) mi

makvit [3.9K]

The extraneous solution of the logarithmic problem $\rm log_3(18x^3)-log_3(2x) = log_3 144$ is -4.

<h3>What is Logarithm?</h3>

A log function is a way to find how much a number must be raised in order to get the desired number.

$a^c =b$

can be written as

$\rm{log_ab=c$

where a is the base to which the power is to be raised,

b is the desired number that we want when power is to be raised,

c is the power that must be raised to a to get b.

Solving the function using the basic logarithmic value, we get,

$\rm log_3(18x^3)-log_3(2x) = log_3 144\\\\ log_3\dfrac{(18x^3)}{(2x)} = log_3 144\\\\ log_3(9x^2)= log_3 144\\\\\text{Taking antilog}\\9x^2 = 144\\x = \sqrt{\dfrac{144}{9}}$

If we solve further we will get that the value of x can be either -4 or 4, if take the value of x as -4, in the beginning then you will get log₃(18(-4)³) as the log of negative value which is impossible.

Hence, x=-4 is an extraneous solution.

Learn more about Logarithms:

brainly.com/question/7302008

8 0

2 years ago

Read 2 more answers

Let R be the region bounded by

loris [4]

a. The area of $R$ is given by the integral

$\displaystyle \int_1^2 (x + 6) - 7\sin\left(\dfrac{\pi x}2\right) \, dx + \int_2^{22/7} (x+6) - 7(x-2)^2 \, dx \approx 9.36$

b. Use the shell method. Revolving $R$ about the $x$ -axis generates shells with height $h=x+6-7\sin\left(\frac{\pi x}2\right)$ when $1\le x\le 2$ , and $h=x+6-7(x-2)^2$ when $2\le x\le\frac{22}7$ . With radius $r=x$ , each shell of thickness $\Delta x$ contributes a volume of $2\pi r h \Delta x$ , so that as the number of shells gets larger and their thickness gets smaller, the total sum of their volumes converges to the definite integral

$\displaystyle 2\pi \int_1^2 x \left((x + 6) - 7\sin\left(\dfrac{\pi x}2\right)\right) \, dx + 2\pi \int_2^{22/7} x\left((x+6) - 7(x-2)^2\right) \, dx \approx 129.56$

c. Use the washer method. Revolving $R$ about the $y$ -axis generates washers with outer radius $r_{\rm out} = x+6$ , and inner radius $r_{\rm in}=7\sin\left(\frac{\pi x}2\right)$ if $1\le x\le2$ or $r_{\rm in} = 7(x-2)^2$ if $2\le x\le\frac{22}7$ . With thickness $\Delta x$ , each washer has volume $\pi (r_{\rm out}^2 - r_{\rm in}^2) \Delta x$ . As more and thinner washers get involved, the total volume converges to

$\displaystyle \pi \int_1^2 (x+6)^2 - \left(7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \pi \int_2^{22/7} (x+6)^2 - \left(7(x-2)^2\right)^2 \, dx \approx 304.16$ <em />

d. The side length of each square cross section is $s=x+6 - 7\sin\left(\frac{\pi x}2\right)$ when $1\le x\le2$ , and $s=x+6-7(x-2)^2$ when $2\le x\le\frac{22}7$ . With thickness $\Delta x$ , each cross section contributes a volume of $s^2 \Delta x$ . More and thinner sections lead to a total volume of

$\displaystyle \int_1^2 \left(x+6-7\sin\left(\frac{\pi x}2\right)\right)^2 \, dx + \int_2^{22/7} \left(x+6-7(x-2)^2\right) ^2\, dx \approx 56.70$

7 0

2 years ago

2. Which of the follow is equivalent to the quantity below? *

Bess [88]

1

2-1=1

Brainliest?pls

3 0

3 years ago