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RUDIKE [14]
3 years ago
9

How can we tell macronutrients apart?

Chemistry
1 answer:
Phoenix [80]3 years ago
3 0

Answer:

if youre talking about macros to lose/gain weight then the Macronutrients refer to carbs, fats and protein — the three basic components of every diet. you cant tell them apart by looking at them but read labels and ingredients listed from packages or you can search them up

hope this helps!

give a follow/brainiest if you can<3

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The number at the end of an isotope's name is the number
Korolek [52]

Answer:

Atomic neutron mass electron number

Explanation:

7 0
3 years ago
1. Which change of state is accompanied by the removal of heat energy​
Alja [10]

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

bit.^{}ly/3a8Nt8n

4 0
3 years ago
Fill in the left side of this equilibrium constant equation for the reaction of benzoic acid (HC_6H_5CO_2) with water.
il63 [147K]

Answer:

[C₆H₅COO⁻][H₃O⁺]/[C₆H₅COOH] = Ka

Explanation:

The reaction of dissociation of the benzoic acid in water is given by the following equation:

C₆H₅-COOH + H₂O  ⇄  C₆H₅-COO⁻  +  H₃O⁺    (1)

The dissociation constant of an acid is the measure of the strength of an acid:

HA ⇄ A⁻ + H⁺        (2)

K_{a} = \frac{[A^{-}][H^{+}]}{[HA]}      (3)

<em>Where the dissociation constant of the acid (Ka) is equal to the ratio of the concentration of the dissociated forms of the acid, [A⁻][H⁺], and the concentration of the acid, [HA].     </em>

So, starting from the equations (2) and (3), the constant equation for the dissociation reaction of benzoic acid in water, of the equation (1), is:

K_{a} = \frac{[C_{6}H_{5}COO^{-}][H_{3}O^{+}]}{[C_{6}H_{5}COOH]}

I hope it helps you!          

6 0
3 years ago
The rate at which a certain drug is eliminated by the body follows first-order kinetics, with a half life of 68 minutes. Suppose
viva [34]

Answer:

The concentration would be; 0.0038 μgmL

Explanation:

Half life, t1/2 = 68 minutes

Initial Conc. [A]o = 0.12/μgmL

Final Conc [A] = ?

Time. k = 340 minutes

ln[A] = ln[A]o - kt

t1/2 = ln2 / k

k = 0.693 / t1/2  = 0.693 / 68 = 0.01019

ln[A] = ln (0.12) - 0.01019 (340)

ln[A] = -2.1203 -3.4646

ln[A] = -5.5849

[A] = 0.00375 ≈ 0.0038 μgmL

3 0
3 years ago
5. Base your answer to the question on the particle diagrams
Luden [163]

Answer:sample 3

Explanation:because if only have one kind of substance which makes it pure

7 0
3 years ago
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