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Alexandra [31]
1 year ago
7

The half-life of cobalt-60 is 5. 20 yr. how many milligrams of a 2. 000 mg sample remain after 6. 55 years?

Chemistry
1 answer:
Stels [109]1 year ago
5 0

0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years, according to radioactive decay.

Given data,

t\frac{1}{2} of Co-60 = 5.20years

amount of sample = 2.000mg initially = 0.002grams

According to radioactive decay,

N_{t} = N_{0}e^{-λt}

(N_{0} - 0.002 )λ = \frac{0.693}{t\frac{1}{2} } = \frac{0.693}{5.20}  = 0.133

According to radioactive decay,

N_{t} = N_{0}e^{-λt}

lnN_{t}  = lnN_{0} - λt

lnN_{t} = ln0.002 - (0.133×6.55)

       = -6.21 - 0.87 = -7.08 = 0.00084g = 0.84mg

Therefore, 0.84 milligrams of a 2. 000 mg sample remain after 6. 55 years.

Learn more about radioactive decay here:

brainly.com/question/1770619

#SPJ4

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Explanation:

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b) Energy change due to transition from n = 1 to n = ∞ ,B^{4+} atom .

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E_1=-13.6\times \frac{5^2}{1^2}eV=-340 eV

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E'=6.022\times 10^{-23} mol^{-1}\times 340eV

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E'=6.022\times 10^{23}\times 340\times 1.60218\times 10^{-22} kJ/mol

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The energy  required to remove the electron in the ground state is 32,804.31 kJ/mol.

c) Energy change due to transition from n = 1 to n = ∞ ,Li^{2+}atom .

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Energy of n = ∞ in an hydrogen like atom:

E_{\infty}=-13.6\times \frac{3^2}{(\infty)^2}eV=0

Let energy change be E.

E=E_{\infty}-E_1=0-(-122.4 eV)=122.4 eV

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Energy for 1 mole = E'

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1 eV=1.60218\times 10^{-22} kJ

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