Is a force created by the water that is displaced by an object.
1 answer:
Answer:
Buoyancy.
Explanation:
Buoyancy is a force created by the water that is displaced by an object. It is directly proportional to the amount of water that is being displaced by an object.
Hence, the greater the amount of water an object displaces; the greater is the force of buoyancy pushing the object up.
The buoyancy of an object is given by the formula;
Where;
Fb = buoyant force of a liquid acting on an object.
g = acceleration due to gravity.
p = density of the liquid.
v = volume of the liquid displaced.
h = height of liquid (water) displaced by an object.
A = surface area of the floating object.
<em>The unit of measurement for the buoyancy of an object is Newton (N).</em>
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Ryan calculates that he requires 4 ice cubes for 250mL of hot tea to reach the optimal drinking temperature by using the specific heat capacity of tea.
A substance's potential to hold heat is indicated by its specific heat capacity. This substance size reflects the amount of heat required to raise a certain volume of a material's temperature by one Kelvin. Specific heat capacity is a distinguishing feature of every substance and is useful for material identification.
Given:
Final temperature of system is 57.8℃
dT1 = 79.1 - 57.8 = 21.3℃
dT2 = 0 - (-8.33) = 8.33℃
dT3 = 57.8 - 0 = 57.8℃
Mass of tea, m1 = 250.0mL = 250.0g = 0.250kg
Specific heat capacity of tea, C1 = 4186 J/kg℃ = Specific heat capacity of water
Specific heat capacity of ice, Ci = 2090 J/kg℃
Mass of each ice cubes, m of i = 18.8g
Latent heat of fusion of ice, Lf = 334 kJ/kg
To find:
No. of ice cubes required = ?
Calculations:
Suppose equilibrium temperature is T, then
Heat released by Tea = Heat gained by Ice
Q1 = Q2
m1x C1x dT1 = mi x Ci x dT2 + mi x Lf + mi x Cw x dT3
0.250x 4186 x 21.3 = mi x (2090 x 8.33 + 3.34 x + 4186 x 57.8)
mi = 0.250 x 4186 x 21.3 / (2090 x 8.33 + 3.34 x + 4186 x 57.8)
mi = 0.0761kg = 76.1g
Mass of ice required = 76.1g
Number of ice cube required will be:
n = Total mass of ice/mass of each ice cube
n = 76.1/18.8
n = 4.04 ice cubes = 4.0 ice cubes
Result:
Ryan requires 4 ice cubes to bring 250mL of hot tea to the optimal drinking temperature.
Learn more about Specific heat capacity here:
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