Help me please!! i’m confused!!

A recipe for brownies calls for 2/3 Cup of chocolate chips for a batch of two dozen brownies. How many chocolate chips will be n

vovikov84 [41]

Answer:

6 cups

Step-by-step explanation:

$(18 \times \frac{2}{3} ) \div 2 =$

$12 \div 2 =$

$6$

8 0

3 years ago

write the slope-intercept form of the equation of the line passing through the point(-5,-2) and parallel to the line y=2x-2

Ivanshal [37]

Point- Slope form is
y - y1 = m (x - x1)
m = slope, (x1, y1) = point
Slope intercept form is y = mx + b
m = slope, b = y-intercept
In order for two lines to be parallel, they must have the same slope, so in this case our slope, m = 2. Now use point-slope form to insert the point and solve.
y--2 = 2 (x --5)
y + 2 = 2x + 10
y = 2x + 8

6 0

3 years ago

Worth 50 points PLUS I'll give the person who answers FIRST and BEST the brainlest answer.

WARRIOR [948]

Okay, this is not really an answer, but I think in 2020, we will be in the 20 trillions. O know that is not the answer you were looking for, but its all I got.

4 0

3 years ago

5. The measure of an intercepted arc is 86, and the measure of the inscribed angle creating the intercepted arc is 3x +

Nonamiya [84]

Answer:

Th correct option is D. 13

Therefore the value of x is 13.

Step-by-step explanation:

Given:

measure of an intercepted arc = 86°

Center Angle = 86°

measure of the inscribed angle creating the intercepted arc= (3x+4)°

Angle Inscribed in arc = (3x+4)°

To Find:

value of x = ?

Solution:

Inscribed Angle Theorem:

The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

$\textrm{Angle Inscribed in arc}=\dfrac{1}{2}\textrm{Center Angle}$

Substituting the values we get

$3x+4=\dfrac{1}{2}86=43\\\\3x=39\\\\x=\dfrac{39}{3}=13\\\\x=13$

Therefore the value of x is 13.

4 0

3 years ago

State whether the triangles could be proven congruent, if possible, by SSS or SAS.

Helen [10]

Answer:

1. SSS

2. SAS

3. SAS

4. SSS

5. SAS

6. SAS

Step-by-step explanation:

1) Side FY ≅ Side CW Given

Side FP ≅ Side CM Given

Side YP ≅ Side MW Given

∴ΔMCW ≅ ΔFPY by the Side-Side-Side (SSS) rule of congruency

2) ∠CBD ≅ ∠BCA given that both are alternate interior angles

Side EB ≅ Side EC and Side DB ≅ Side CA Given

ΔBED ≅ ΔAEC by Side-Angle-Side (SAS) rule of congruency

3. ∠SVU ≅ ∠SVT Given

Side SV ≅ Side SV by reflexive property

Side VT ≅ Side VU Given

∴ ΔVSU ≅ ΔVST by Side-Angle-Side (SAS) rule of congruency

4. Side MN ≅ Side QP Given

Side MQ ≅ Side NP Given

Side NQ ≅ Side NQ by reflexive property

∴ΔQNM ≅ ΔQNP by the Side-Side-Side (SSS) rule of congruency

5. Indirect proof

Side GL ≅ Side HL Given

Side GJ ≅ Side HK Given

∠JLG ≅ ∠HLK vertically opposite angles

By sine rule

GJ/sin(∠JLG) = GL/n(∠GJL)

Similarly

HK/sin(∠HLK) = HL/n(∠HKL)

∴ ∠GJL ≅ ∠HKL

∴ ∠LGJ ≅ ∠LHK third angle of two triangles given the other two angles are congruent

∴ΔQNM ≅ ΔQNP by the Side-Angle-Side (SAS) rule of congruency

6. ∠XZY ≅ ∠XZW Supplementary ∠s with ∠XZY = 90°

Side XZ ≅ Side XZ by reflexive property

Side ZW ≅ Side ZY Given

∴ ΔXYZ ≅ ΔXWZ by Side-Angle-Side (SAS) rule of congruency.

3 0

3 years ago