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Shkiper50 [21]
2 years ago
8

What fraction is equivalent to 3/10 and has a denominator of 100

Mathematics
2 answers:
rosijanka [135]2 years ago
7 0

Answer:

30/100

Step-by-step explanation:

This should be relatively easy since if the denominator is 100 then x/100 has to = 3/10

Since the denominator 10 has to be 100, you multiply by 10.

3 x 10 = 30

Irina18 [472]2 years ago
7 0

Answer:

30/100

Step-by-step explanation:

3/10 = x/100

now, what times 10 gives us 100. To find this out, divide 100 by 10, and we get 10. Now in fractions, whatever you do with the denominator has to be done with the numerator too. So, if 10 x 10 = 100, then 3 x 10 gives us 30.

Therefore, our answer is 30/100, and yes, when you break this down, or in other words, simplify, you will get 3/10.

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Find the measure of angle x in the figure below: Two triangles are shown such that one triangle is inverted and they share a com
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Y can be found by setting the 3 angles in the bottom triangle equal to 180 degrees like so:

45 + 55 + y = 180

100 + y = 180 (Simplify)

y = 80 (Subtract 100 from both sides)

Angles x and y are opposite angles, so they are equal to each other. This means that x = 80 degrees also.
7 0
3 years ago
What's the answer???
mafiozo [28]
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3 years ago
In the coordinate plane line p had slope 8 and y intercept (0,5). Line r is the result of dilating line p by a factor of 3 with
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3 years ago
A jogger ran 3 miles due east of his house. then he ran 5 miles at a heading of 30o east of north (or 30o ne). how far is he fro
Natasha_Volkova [10]

Magnitude of the net displacement: 7.0 miles

Step-by-step explanation:

In order to find the total displacement of the man, we have to resolve each displacement along the x- and y- direction.

Taking x as positive x direction and y as positive north direction:

- The first motion is 3 miles due east, so

A_x = 3 mi\\A_y = 0

- The second motion is 5 miles at 30^{\circ} east of north, so:

B_x = 5 sin 30^{\circ}=2.5 mi\\B_y = 5 cos 30^{\circ}=4.3 mi

So the components of the net displacement are

R_x = A_x + B_x = 3 + 2.5 = 5.5 mi\\R_y = A_y+B_y = 0 + 4.3 = 4.3 mi

And so the magnitude of the net displacement is

d=\sqrt{R_x^2+R_y^2}=\sqrt{5.5^2+4.3^2}=7.0 mi

So, he is 7.0 miles far from the house.

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

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3 years ago
Is it possible to find a value of $x$ so that the value of the surface area (in square inches) is equal to the value of the volu
Annette [7]

The box has volume

11 in × 3 in × <em>x</em> in = 33<em>x</em> in³

and surface area

2 (11 in × 3 in + 11 in × <em>x</em> in + 3 in × <em>x</em> in) = (66 + 28<em>x</em>) in²

The volume and area have the same value if

33<em>x</em> = 66 + 28<em>x</em>

Solve this equation for <em>x</em> :

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5<em>x</em> = 66

<em>x</em> = 66/5 = 13.2

7 0
3 years ago
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